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Katen [24]
4 years ago
6

Find the areas of the parallelogram whose vertices are given below. ​A(negative 1​,4​) ​B(4​,0​) ​C(12​,3​) ​D(7​,7​) The area o

f parallelogram ABCD is nothing square units.

Mathematics
1 answer:
tankabanditka [31]4 years ago
5 0

Answer:

So the parallelogram is in the first and second quadrants.

Step-by-step explanation:

From Exercise we have that the parallelogram have a vetrices:

A(negative 1​,4​) ​B(4​,0​) ​C(12​,3​) ​D(7​,7​). We use a site geogebra.org to plof a graph for the given parallelogram.

From the graphs we can see that the parallelogram is mostly in the first quadrant and smaller in the second quadrant. So the parallelogram is in the first and second quadrants.

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Please help on B C D ONLY PLEASE
Rama09 [41]

The answer for B is: 40 - (7.50 x 4) = 10 Because 7.50 x 4 = 30 and 40 - 30 = 10 So they are left with $10 after paying for the tickets

The answer for C is: Miguel and his 3 friends started with $40 and had a fee of $7.50 for each ticket and there are 4 people. 4 x 7.50 = 30 and 40 - 30 = 10 so they are left with $10 to spend on snacks and other stuff!

Idk the answer for D sorry about that!

Hope this helps!

5 0
4 years ago
What two numbers multiply to give 36 but add up to -13
mars1129 [50]
The numbers -9 and -4 add up to -13 and multiply to get 36

I hope this helped :)
5 0
3 years ago
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Which shape is a Parallelogram?
mariarad [96]
The top left is the correct answer, because the sides are parallel.

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5 0
3 years ago
Find the 95% confidence interval for estimating the population mean μ
AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

  • \displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}

We are given these variables:

  • \overline{x}=50
  • n=60
  • \sigma=10

Plug these values into the formula for the confidence interval:

  • \displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

  • \displaystyle \frac{1-C}{2}=A

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

  • \displaystyle \frac{1-.95}{2}=.025

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

  • t^*=1.96

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

  • \displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}

We can calculate the confidence interval, using this formula, to be:

  • \boxed{(47.4697, \ 52.5303)}

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0
2 years ago
I dont know how to do this...<br>I need #48
agasfer [191]
Just switch the x and the 3
8 0
3 years ago
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