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Katen [24]
3 years ago
6

Find the areas of the parallelogram whose vertices are given below. ​A(negative 1​,4​) ​B(4​,0​) ​C(12​,3​) ​D(7​,7​) The area o

f parallelogram ABCD is nothing square units.

Mathematics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

So the parallelogram is in the first and second quadrants.

Step-by-step explanation:

From Exercise we have that the parallelogram have a vetrices:

A(negative 1​,4​) ​B(4​,0​) ​C(12​,3​) ​D(7​,7​). We use a site geogebra.org to plof a graph for the given parallelogram.

From the graphs we can see that the parallelogram is mostly in the first quadrant and smaller in the second quadrant. So the parallelogram is in the first and second quadrants.

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Plz answer will be marked BRAINLIEST
Anastaziya [24]
A=90 degrees divide by 5
=18 degrees
2c+a=90
2c+18=90
2c=90-18
2c=72
divide each side by 2
c=36
therefore:
2c=72

b=4a+c
b=4(18)+36
b=72+36
b=108
3 0
3 years ago
Read 2 more answers
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Harman [31]

Answer:

μ =2.23

\sigma_x^2= 1.49

\sigma_x=1.22

Step-by-step explanation:

Radio(x)                            weeks                           P(x)

0                                         5                                 5/100 = 0.05

1                                           27                               27/100=0.27

2                                          27                                 27/100 = 0.27

3                                         27                                 27/100 = 0.27  

4                                           9                                    9/100=0.09

5                                             5                                    5/100=0.05

We know that

Mean ,μ

\mu =\sum x.P(x)

μ = 0 x 0.05 + 1 x 0.27 + 2 x 0.27 + 3 x 0.27 + 4 x 0 .09 + 5 x 0.05

μ =2.23

\sigma_x^2= \sum x^2\times P(x)-(\sum x.P(x))^2

\sigma_x^2= 0^2\times 0.05+ 1^2\times 0.27+ 2^2\times 0.27+ 3^2\times 0.27+ 4^2\times 0.09+5^2\times 0.05-2.23^2

\sigma_x^2= 1.49

\sigma_x= \sqrt{\sigma_x^2}

\sigma_x=1.22

7 0
3 years ago
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alisha [4.7K]

Answer:

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Step-by-step explanation:

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5 0
2 years ago
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6. Use the image below to find the missing value.
Katarina [22]

Option C:

The value of m is 4.

Solution:

Given data:

AB = 4m – 15

BC = 5m –6

AC = 15

<u>To find the value of m:</u>

Using segment addition postulate,

AB + BC = AC

4m – 15 + 5m –6 = 15

Arrange the like terms together.

4m + 5m – 15 – 6 = 15

9m – 21 = 15

Add 21 on both sides of the equation,

9m = 36

Divide by 9 on both sides of the equation.

m = 4

The value of m is 4.

Option C is the correct answer.

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