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djyliett [7]
3 years ago
5

Let z =38 (cos(pi/8)+ i sin(pi/8)) and w = 2 (cos( pi/16 ) + i sin(pi/16))

Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

zw=76 * (cos(\frac{3\pi}{16}) +isin(\frac{3\pi}{16}) )

Step-by-step explanation:

Given

z =38 (cos(\frac{\pi}{8})+ i sin(\frac{\pi}{8}) and

w = 2 (cos(\frac{\pi}{16} ) + i sin(\frac{\pi}{16})

Required

Determine zw

Given that:

x = v_1(cos(a) + isin(a)) and y = v_2(cos(b) + isin(b))

x * y = (v_1 * v_2)*((cos(a+b) + isin(a+b))

So, we have:

zw=(38 * 2) * (cos(\frac{\pi}{8} + \frac{\pi}{16}) + isin(\frac{\pi}{8} + \frac{\pi}{16}))

zw=76 * (cos(\frac{2\pi + \pi}{16})+isin(\frac{2\pi + \pi}{16}))

zw=76 * (cos(\frac{3\pi}{16}) +isin(\frac{3\pi}{16}) )

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