Answer:
See explaination
Step-by-step explanation:
Probability is the number of desired outcomes over the total outcomes.
1) You want to find Oranges, so that is your desired outcome:
There are 4 oranges in the bowl.
Now sum up all the fruits to get the total:
9+4+7+3+6 = 29
Therefore you have 4/29
2) Same idea, count the peaches and put it over total:
3/29
3) This time, you still want to use the same idea, but its just your desired outcomes that have increased. So instead of just having one fruit, now you want to add the total of 2 fruits as your desired outcome.
(9+4)/29
= 13/29
4) To find the probability of a fruit other than a plum, you can use complementary counting. Since the maximum probability is one, we can find what we dont want, and the outcome of that subtracted from one must be the results that we want.
So a plum is 6/29
1-6/29 = 23/29
5) Same idea as what is used in problems 3 and 4, just a combination of the 2.
(4+3)/29
1-7/29
= 22/29
The answer is 36.
You subtract or decrease the number by 8 every time.
Answer:
5.3624785e+55
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2
(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1
1 + 2 sinq*cosq (*)
Setting a = b = q in the trig identity:
sin(a+b) = sina*cosb + cosa*sinb
sin(2q) = (**)
sinq*cosq + cosq*sinq => as both terms are identical
2 sinq*cosq
Combining (*) and (**)
(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)
= 1 + sin(2q)
Hence
(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides
(sinq + cosq)^2 - 1 = sin(2q)
The last statement is what we are trying to prove.
Thank you,
MrB
Answer:
x = -1
Step-by-step explanation:
