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3 years ago

R(x)=x(65-3x)

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Can you please help me solve something

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Help me find the slope

Alex Ar [27]

M= -6/5
hope this helped!!

4 0

3 years ago

PLEASE HELP ME ASAP!! ILL MARK BRIANLIEST AND GIVE EXTRA POINTS

lara [203]

Answer:

$x \leqslant \frac{5}{3}$

Step-by-step explanation:

$3x \leqslant 5 \\ 3x \div 3 \leqslant 5 \div 3\\ x \leqslant \frac{5}{3}$

explanation for second step:

you divide each side by 3 to get rid of the '3' in '3x'

6 0

4 years ago

How do the graphs of y=1/x and y=5/x+6<br><br> compare?

oee [108]

Answer: The graph is attached.

Step-by-step explanation: The given functions whose graphs are to be compared are as follows:

$y=\dfrac{1}{x},~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)\\\\\\y=\dfrac{5}{x}+6.~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

In the attached figure, the graphs of both (A) and (B) are shown. We can easily see see from there, the shapes of both the graphs are same.

But, at x = 0, y = ∞ and at x = ∞, y = 0 in graph (A).

At x = 0, y = ∞ and at x = ∞, y = 6 in graph (B).

Thus, the comparison can be seen in the figure very clearly.

8 0

3 years ago

In a long division exercise the divisor is 8x5−4x. What is the degree of the remainder for which the division process can be st

labwork [276]

Answer:

The degree of the remainder should be 4 for the division process to be stopped

Step-by-step explanation:

From the question, we have the degree of the divisor as 5

So, for the division process to be stopped, the degree of the remainder should be one less than the degree of the divisor

Once the degree of the remainder is less than the degree of the divisor, we have no option that to stop and not proceed further with the division

So in the case of the particular question, the degree of the remainder should be of degree 4

4 0

3 years ago

How do you solve this problem?

Eduardwww [97]

$\bf \displaystyle \int \left( 4+\cfrac{5}{t}+\cfrac{10}{t^2} \right)dt\\\\
-----------------------------\\\\
\displaystyle \int 4 \cdot dt+5\int \cfrac{1}{t}\cdot dt+10\int t^{-2}\cdot dt
\implies 
4t+5ln|t|-\cfrac{10}{t}+C$

3 0

4 years ago