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AlexFokin [52]
3 years ago
8

The least common denominator of the two fractions is 30. If you add the two denominators, their sum is 17. What are the denomina

tors
Mathematics
1 answer:
QveST [7]3 years ago
8 0
The answer could be 2 and 15
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Heights of adult males are known to have a normal distribution. a researcher claims to have randomly selected adult males and me
8090 [49]

Answer:

The sum of the probabilities is greater than 100%; and the distribution is too uniform to be a normal distribution.

Step-by-step explanation:

The sum of the probabilities of a distribution should be 100%.  When you add the probabilities of this distribution together, you have

22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121

This is more than 100%, which is a flaw with the results.

A normal distribution is a bell-shaped distribution.  Graphing the probabilities for this distribution, we would have a bar up to 22; a bar to 24; a bar to 21; a bar to 26; and bar to 28.

The bars would not create a bell-shaped curve; thus this is not a normal distribution.

3 0
3 years ago
Read 2 more answers
Choose 3 values that would make thi inequalitie true 28+x>42
Y_Kistochka [10]

9514 1404 393

Answer:

  14.01, 493, 87

Step-by-step explanation:

Subtracting 28 from both sides tells you the range of values you need to be looking at.

  28 + x > 42

  x > 14

Any values more than 14 will make the inequality true. Three of them are ...

  14.01, 493, 87

4 0
3 years ago
What is 612.0÷0.06<br><br>please help me​
erik [133]

Answer:

10,200

Step-by-step explanation:

8 0
3 years ago
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The formula Y=X⁴-4X³+3X² is growing?
miskamm [114]

Answer:

The best way to know weather the formula y=x⁴-4x³+3x² is growing or not, is by graphing it.

As you can see in the attached picture:

  • For -inf<x< 0 the graph decreases.
  • For 0<x<0.634 the graph is growing
  • For 0,634<x<2.366 the graph decreases
  • For 2.366<x<+inf the graph is growing.

Therefore, the polynomial grows in the intervals stated before.

6 0
3 years ago
Place the numbers 0 to 8, inclusive, in the magic square so that the sum of the numbers in each row, column, and diagonal is the
ehidna [41]

Answer: See attached table

Step-by-step explanation:

\begin{table}[]\begin{tabular}{lllll} &  &  &  &  \\ &  &  &  &  \\ &  &  &  &  \\ &  &  &  & \end{tabular}\end{table}+---+---+---+

| 1 | 8 | 2 |

+---+---+---+

| 6 | 4 | 2 |

+---+---+---+

| 5 | 0 | 7 |

+---+---+---+

<u>Proofs:</u>
First row: 1+6+5 = 12

Second row: 8+4+0 = 12

Third row: 2+2+7 = 12

First column: 1+8+2 = 12

Second column: 6+4+2 = 12

Third column: 5+0+7 = 12

Diagonal starting from top left to bottom right: 1+4+7 = 12

Diagonal staring from top right to bottom left: 2+4+5 = 12

6 0
2 years ago
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