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2 years ago

The interquartile range is determined by the formula _________.

Mathematics

1 answer:

Elena-2011 [213]2 years ago

4 0

Answer:

Step-by-step explanation:

The inter quartile range is determined by the formula Third quartile - first quartile.

In a set, an inter quartile range is a measure of where the bulk of the data's lie

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I have 3 red jawbreakers 2 green 5 orange jawbreakers and 1 purple jaw breaker which color of jawbreaker can be represented as a

Sonbull [250]

2 green jawbreakers
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2 years ago

The sum of 5 consecutive even numbers is 100. What is the first number in this sequence?

gayaneshka [121]

Answer:

Step-by-step explanation:

Let's represent this with an equation, where x is the first number. The next number must be x+2, because it has to be even, not x+1, and the rest continue the same way:

x+(x+2)+(x+4)+(x+6)+(x+8) = 100

Solve for x.

5x+20 = 100

5x = 80

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2 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

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2 years ago

The Maximus Electric Company will increase employee's yearly wages by 2.5% next year. An employee whose

Mamont248 [21]

Answer:

46,125

Step-by-step explanation:

2.5% = .025

45,000 * .025 = 1,125

45,000 + 1,125 = 46,125

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2 years ago

Plz help brainiest to the correct answer!

zysi [14]

Answer is highlighted in brown. Hope this helps.

5 0

2 years ago

Read 2 more answers