The distance would be 21. to find the difference, add the absolute values so 12+9, which equals 21
A high outlier in a data sat causes the mean and median value to move slightly towards the outlier
Unfortunately, your problem statement appears to be incomplete. What distance are you talking about? Have you an illustration to share? How does 0.25 inches fit into this problem? Please try again. Double-check to ensure that you have shared all of the problem you wish to solve.
