An.swer:
171.68
Step-by-step explanation:
Well all you have to do is find the common denominator then use it to subtract
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
1 mm
Km etc
Hm etc
Dam etc
M 0.001
Dm 0.01
Cm 0.1
MM 1
(5 * sqrt(x^7))^3
Recall sqrt(x^2)=x
So we get (5*x^6 )^3
5*3 is 25, 6*3 is 18 (and exponent to an exponent multiplies)
Therefore the answer is 25x^18