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Alja [10]
3 years ago
7

Can you please help me figure out this answer? Please and thank you

Mathematics
1 answer:
galben [10]3 years ago
7 0

Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.

The formula for P is P = 2W + 2L.

Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:

P = 2(3 1/2 yds) + 2(4 2/3 yds)

= 7 yds + 9 1/3 yds = 16 1/3 yds, total.

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