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Alja [10]
3 years ago
7

Can you please help me figure out this answer? Please and thank you

Mathematics
1 answer:
galben [10]3 years ago
7 0

Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.

The formula for P is P = 2W + 2L.

Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:

P = 2(3 1/2 yds) + 2(4 2/3 yds)

= 7 yds + 9 1/3 yds = 16 1/3 yds, total.

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If the endpoints of segment AB are A(-4,5) and B(2,-5),<br><br>please help! ​
nadezda [96]

Answer:

d = \sqrt[2]{34}

Step-by-step explanation:

We are solving for the segment of AB. Note that it is a line segment, so there will be end points, those being A(-4, 5) & B(2, -5).

Use the following distance formula:

<em />distance<em> </em>(d) = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - x_{2})^2 }

Let:

Point B(2 , -5) = (x₁ , y₁)

Point A(-4 , 5) = (x₂ , y₂)

Plug in the corresponding numbers to the corresponding variables.

d = \sqrt{(-4 - 2)^{2} + (5 - (-5))^{2} }

Simplify. Remember to follow PEMDAS. First, solve the parenthesis, then the powers, then add, and then finally square root.

d = \sqrt{(-6)^{2} + (5 + 5)^{2}  } \\d = \sqrt{(-6 * -6) + (10)^2} \\d = \sqrt{(36) + (10 * 10)} \\d = \sqrt{36 + (100)} \\d = \sqrt{136}

Simplify:

d = \sqrt{136} = \sqrt{2 * 2 * 2 * 17}  = \sqrt[2]{17 * 2} = \sqrt[2]{34}

d = \sqrt[2]{34} is your answer.

~

3 0
4 years ago
Lisa's dog is 11 pounds heavier than Marcia's dog. Let m represent the weight of Marcia's dog. Write a variable expression to re
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Answer:

M+11=L

Step-by-step explanation:

  • M= the weight of Marcia's dog.
  • L equals the weight of Lisa's dog.

The weight of Marcia's dog plus 11 = the weight of Lisa's dog.

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3 years ago
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Answer:

B. (2 + 5).

Step-by-step explanation:

18 + 45 = 63

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So 63 is a multiple of 7.

The answer is (2 + 5)  (=7).

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vampirchik [111]

Answer:

I believe 25%

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There are four equally likely outcomes: HH, HT, TH and TT. Of these, one of these match the criterion given ("the first will come up heads and the second tails”). So the probability is 1/4= 25%.

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