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pentagon [3]
3 years ago
12

Find the area between the curves x=-2,x=3,y=4x,y=x-5

Mathematics
1 answer:
mixas84 [53]3 years ago
5 0
Those are all lines...

So the x interval is from -2 to 3, because of x=-2 and x=3

The upper line is y(u)=4x and the lower line is y(l)=x-5

So the area between the two lines is:

A=⌠y(u)-y(l) dx

A=⌠4x-x+5 dx

A=⌠3x+5 dx

A=[3x^2/2+5x]

A=[(3x^2+10x)/2], x=[-2,3]

A=(1/2)(27+30-(12-20))

A=(1/2)(57+8)

A=(1/2)(65)

A=32.5 u^2
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Answer:

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3 0
3 years ago
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s344n2d4d5 [400]
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3 years ago
13. Which is Not independent <br><br> 14 . 2 coins tossed , probability
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3 0
3 years ago
Read 2 more answers
What is 3/4 of 16/21? worked out please
timofeeve [1]
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And then simplify the numerator ad denominator

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And simplify the numerator and denominator again

= \frac{\ 1 \times 16}{4 \times 7} = \frac{\ 1 \times 4}{1 \times 7}

And we are finally left with the answer which is \frac{4}{7}
5 0
4 years ago
Need help any body help please
lutik1710 [3]
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6 0
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