Yes you must update or do something first but then you can
Answer:
C
Explanation:
Putting all government forms on the city web site is the least activity likely to be effective in the purpose of reducing digital divide.
Holding basic computer classes at the community centers will very much help to reduce the digital divide.
Providing free wireless internet connections at locations in low-income neighborhood will also reduce the gap of digital divide
Requiring that every city school has computers that meet a minimum hardware and software will made computing resources available to users thereby reducing digital divide.
Answer: Internet service provider
Explanation:
Answer:
A computerized light dimmer is one helpful development in lighting equipment. Computerized light dimmers help to control the brightness of light. These dimmers lower or increase the intensity of light. I first noticed light dimmers in a scene from the movie Children of Men. In a war scene, innocent people are shown running helter-skelter to save their lives. Artificial lights are used in scene to create that dark appearance in broad daylight, which makes the scene look gloomy and scary. It helped to generate the feeling of uncertainty and suspense through the proper use of lights. Light dimmers help light designers to create the exact atmosphere that the director demands for a scene. Also, because of dimmers, a light designer need not use extra accessories to diffuse light or make the scene brighter.
Explanation:
This is Plato's sample answer so take pieces out.
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
