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Ad libitum [116K]
3 years ago
14

Sodium atomic radius 1.90

Chemistry
1 answer:
lakkis [162]3 years ago
4 0

<u>Answer:</u>

<u>For a:</u> The increasing of atomic radius is:

Al < Mg < Na

<u>For b:</u> The pH of the solution of sodium oxide is greater than 7.

<u>Explanation:</u>

  • <u>For (a):</u>

Atomic radius is defined as the distance of the nucleus to the outermost shell containing electrons.

It decreases as we move from left to right in a period because electrons get added up in the same shell and effective nuclear charge increased which results in the shrinkage of the atom.

Sodium lies in Period 3, group 1. Its atomic radius is 1.90

Magnesium lies in Period 3, group 2. Its atomic radius is 1.60

Aluminium lies in Period 3, group 3. Its atomic radius is 1.32

The increasing of atomic radius will be:

Al < Mg < Na

The mathematical values proves the result.

  • <u>For (b):</u>

There are 3 types of solution based on pH:

  • If pH > 7, the solution is basic in nature.
  • If pH < 7, the solution is acidic in nature.
  • If pH = 7, the solution is neutral in nature.  

When a metal reacts with oxygen present in air, it forms basic oxide which simply means when they react with water, they form basic solution.

The chemical equation for the reaction of sodium (metal) with oxygen present in air and reaction with water of the product so formed are as follows:

4Na+O_2\rightarrow 2Na_2O

Na_2O+H_2O\rightarrow 2NaOH\text{ (base)}

Sodium forms a basic solution when its oxide reacts with water, therefore the pH of the solution will be greater than 7.

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Answer:

0.51M

Explanation:

Given parameters:

Initial volume of NaBr = 340mL

Initial molarity  = 1.5M

Final volume  = 1000mL

Unknown:

Final molarity = ?

Solution;

This is a dilution problem whereas the concentration of a compound changes from one to another.

In this kind of problem, we must establish that the number of moles still remains the same.

    number of moles initially before diluting = number of moles after dilution

Number of moles  = Molarity x volume

Let us find the number of moles;

          Number of moles  = initial volume x initial molarity

Convert mL to dm³;

                  1000mL  = 1dm³

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Number of moles  = initial volume x initial molarity  = 0.34 x 1.5 = 0.51moles

Now to find the new molarity/concentration;

               Final molarity  = \frac{number of moles}{Volume}    = \frac{0.51}{1}    = 0.51M

We can see a massive drop in molarity this is due to dilution of the initial concentration.

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How many molecules are in 88g of carbon dioxide?
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Answer:

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Explanation:

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