Dude look it up on google bc i think we dont know the answer and i bet you will get a better answer there
Answer:
Hope it help you
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Explanation:
It would be <u>8910 ug</u>
REAL NAME - SHRESTH DUBEY
Answer:
The mass of oxygen needed to be pumped in the aquarium is 10 g
Explanation:
Here the value of the degree of solubility of oxygen in water is sought
The solubility of oxygen in fresh water is approximately 1.22 × 10⁻³ mol·dm⁻³ which is equivalent to approximately 40 mg/L
The volume of water the aquarium holds = 250 L
The mass of oxygen required = The solubility of oxygen in water × (The volume of water in the aquarium)
Therefore, the mass of oxygen needed to be pumped in the aquarium = 40 mg/L × 250 L = 10,000 mg
1,000 mg = 1 g
∴ 10,000 mg = 10 g
The mass of oxygen needed to be pumped in the aquarium = 10,000 mg = 10 g.
Answer:
The reaction will proceed to the left to attain equilibrium.
Explanation:
The question is missing but I guess it must be about <em>how the reaction will proceed to attain equilibrium.</em>
First, we have to calculate the partial pressures using the ideal gas equation.


Now, we have to calculate the reaction quotient (Qp).

Since Qp > Kp, the reaction will proceed to the left to attain equilibrium.