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beks73 [17]
3 years ago
5

The Freeman family is barbecuing veggie burgers, corn cobs, and mushroom caps in their local park. If 3 8 of the items barbecued

are veggie burgers, and 1 3 of the items barbecued are corn cobs, what fraction of barbecued items are mushroom caps? 17 24 4 11 3 8 1 8 7 24
Mathematics
1 answer:
sineoko [7]3 years ago
8 0

Answer: 7/24

Step-by-step explanation:

Fraction of the items barbecued that are veggie burgers = 3/8

Fraction of the items barbecued that are corn cobs = 1/3

The fraction of the items barbecued that are mushrooms caps will be:

= 1 - (3/8 + 1/3)

The lowest common multiple of 8 and 3 is 24.

= 1 - (3/8 + 1/3)

= 1 - [(3/8 × 24) + [(1/3 × 24)]

= 1 - (9/24 + 8/24)

= 1 - 17/24

= 7/24

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The amount of time workers spend commuting to their jobs each day in a large metropolitan city has a mean of 70 minutes and a st
Zepler [3.9K]

Answer:

At least 75% of these commuting times are between 30 and 110 minutes

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

In this question:

Mean of 70 minutes, standard deviation of 20 minutes.

Since nothing is known about the distribution, we use Chebyshev's Theorem.

What percentage of these commuting times are between 30 and 110 minutes

30 = 70 - 2*20

110 = 70 + 2*20

THis means that 30 and 110 minutes is within 2 standard deviations of the mean, which means that at least 75% of these commuting times are between 30 and 110 minutes

8 0
3 years ago
5²+3³.2³/4³=?<br><br> Thanks...
solong [7]
5^{2} =25 \\  3^{3} =27 \\  2^{3} =8 \\  4^{3} =64 \\  \\ 27.8=216 \\ 216+25=241 \\  \\  \frac{241}{64} =3,76 \\  \\\framebox[1.1\width]{Good Luck!} \par
4 0
3 years ago
Read 2 more answers
A national survey of companies included a question that asked whether the company had at least one bilingual telephone operator.
nirvana33 [79]

Answer:

The first option is correct. Option A is correct.

LCL = 0.270, and UCL = 0.397

80% Confidence interval = (0.270, 0.397)

Step-by-step explanation:

The data for Y and N for the 90 companies is attached to this solution provided.

Y represents companies with at least 1 bilingual operator and N represents companies with no bilingual operator.

The number of Y in the data = 30

Hence, sample proportion of companies with at least one bilingual operator = (30/90) = 0.3333

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion = 0.3333

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 80% confidence level for sample size of 90 is obtained from the z-tables.

Critical value = 1.280

Standard error of the mean = σₓ = √[p(1-p)/n]

p = sample proportion

n = sample size = 90

σₓ = √[0.3333×0.6667)/90] = 0.0496891568 = 0.04969

80% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.3333 ± (1.28 × 0.04969)

CI = 0.3333 ± 0.0636021207

80% CI = (0.2696978793, 0.3969021207)

80% Confidence interval = (0.270, 0.397)

Hope this Helps!!!

3 0
3 years ago
What is the answer to this question?
andrezito [222]
The second answer which is b the answer is 10 all you do is combine  like terms then plug it in and do the next step ill reply when i get the second one


6 0
3 years ago
Label the terms in the expression as constant, linear, and quadratic
Masteriza [31]

Answer:

Step-by-step explanation:

4x^2 is the quadratic

3x is linear

-6 is the constant.

8 0
3 years ago
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