Rewrite the fractions with their LCD.

Divide 794.1 by by 76.1 round off your answer to two decimal places

valentina_108 [34]

Answer:

794.1 ÷ 76.1= 10.4349.54

Round to the nearest whole number = 6

Round to the nearest tenth=5.6

Round to the nearest Hundredths=5.63

Round to the nearest Thousandth=5.635

7 0

3 years ago

PLEASE HELP ME AFAP!

elixir [45]

Answer:

95 pizzas i think i honestly don't know I'm really sorry if I'm wrong

Step-by-step explanation:

sorryyy

3 0

3 years ago

Read 2 more answers

How do I give points and how do I earn points HELP ME

Alona [7]

Answer:

You can give points by asking a question. Anyone who answers that question will receive the points. You can earn points by answering questions yourself!

Step-by-step explanation:

Hope that helps!

6 0

3 years ago

Find the domain for the rational function f of x equals quantity x plus 1 end quantity divided by quantity x minus 2 end quantit

Elena L [17]

Answer:

$(- \infty, 2), (2, \infty)$

Step-by-step explanation:

Given the function:

$f(x) = \dfrac{x+1}{x-2}$

To find:

Domain of the function.

Solution:

First of all, let us learn about definition of domain of a function.

Domain of a function is the valid input values that can be provided to the function for which output is defined.

OR

Domain of a function $f(x)$ are the values of $x$ for which the output $f(x)$ is a valid value.

i.e. The function does not tend to $\infty$ or does not have $\frac{0}0$ form.

So, we will check for the values of $x$ for which $f(x)$ is not defined.

For value to tend to $\infty$ , denominator will be 0.

$x-2\neq 0 \\\Rightarrow x \neq 2$

So, the domain can not have x = 2

Any other value of x does not have any undefined value for the function $f(x)$ .

Hence, the answer is:

$\bold{(- \infty, 2), (2, \infty)}$ [2 is not included in the domain].

7 0

4 years ago

Intercept from a table

gladu [14]

$\bf \begin{array}{ccll} x&y\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \boxed{14}&\boxed{-5}\\ 21&-3\\ \boxed{28}&\boxed{-1} \end{array}\impliedby \textit{we'll use two points to get the slope}$

$\bf (\stackrel{x_1}{14}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{28}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-5)}{28-14}\implies \cfrac{-1+5}{28-14} \\\\\\ \cfrac{4}{14}\implies \cfrac{2}{7} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{2}{7}(x-14) \\\\\\ y+5=\cfrac{2}{7}x-4$

now, to get the y-intercept, we simply set x = 0 and solve for y, and to get the x-intercept, we set y = 0 and solve for x.

$\bf \stackrel{\textit{y-intercept, x = 0}}{y+5=\cfrac{2}{7}(0)-4}\implies y+5=-4\implies y=-9\qquad \qquad \stackrel{y-intercept}{(0~,-9)}\\\\ -------------------------------\\\\ \stackrel{\textit{x-intercept, y = 0}}{(0)+5=\cfrac{2}{7}x-4}\implies 5=\cfrac{2x}{7}-4\implies 9=\cfrac{2x}{7}\implies 63=2x \\\\\\ \cfrac{63}{2}=x\implies 31\frac{1}{2}=x\qquad \qquad \qquad \qquad \qquad \qquad \qquad \stackrel{x-intercept}{\left( 31\frac{1}{2}~,~0 \right)}$

8 0

3 years ago