Which subtraction problem does NOT require zero pairs to solve using chips ? ( PLEASE ANSWER ASAP )

Mathematics

1 answer:

Mama L [17]3 years ago

7 0

Answer:

Step-by-step explanation:

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The amount of kerosene, in thousands of liters, in a tank at the beginning of any day is a random amount Y from which a random a

Tems11 [23]

Find the marginal density for $Y$ by integrating the joint PDF over all possible values of $x$ :

$f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\int_0^y2\,\mathrm dx$

$\implies f_Y(y)=\begin{cases}2y&\text{for }0$

Then the density of $X$ conditioned on $Y$ is

$f_{X|Y}(x\mid y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\frac1y$

for $0$ and undefined elsewhere.

Thus

$P(0.25$

= = =

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4 years ago

Jill bought a pound of strawberries for $4.00. What is the price, in dollars, per ounce of strawberries? (1lb = 16 oz)

kvv77 [185]

4/16=.25
$0.25/oz
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8 0

3 years ago

Read 2 more answers

What is the polar form of Negative 9 StartRoot 3 EndRoot + 9 i?

kondor19780726 [428]

Answer:

Step-by-step explanation:

In the rectangular complex number -9√3 + 9i, which has a standard form a + bi, the a = -9√3 and the b = 9. We need this in polar form (r, θ) where

$r=\sqrt{a^2+b^2}$ and filling in:

$r=\sqrt{(-9\sqrt{3})^2+(9)^2 }$ (notice we do not put the i in there with the 9).

$r=\sqrt{243+81}$ so

r = 18. Now let's move on to the angle, which is a little more difficult. The angle is found in the inverse tangent ratio:

$tan^{-1}(\frac{b}{a})$ so filling that in, we have:

$tan^{-1}(\frac{9}{-9\sqrt{3} })=\frac{1}{-\sqrt{3} }$ Since tangent is the side opposite over the side adjacent, y is positive and x is negative in the second quadrant. This is a 30 degree angle in QII, which has a reference angle of 150 degrees. This angle in radians is $\frac{5\pi}6}$ , so the polar form of that number is (18, $\frac{5\pi}{6}$ )