Which subtraction problem does NOT require zero pairs to solve using chips ? ( PLEASE ANSWER ASAP )

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

2 years ago

Write the equation of a line that is parallel to the x-axis and passes through the point (8, 3)

sleet_krkn [62]

Answer:

y=3

Step-by-step explanation:

7 0

2 years ago

Suppose a city with population of 400,000 has been growing at a rate of 5% per year. If this rate continues, find the populati

kakasveta [241]

The number of years value isn't given, we could use an hypothetical value, which can be substituted for the correct number of years given in your exercise in other to find the exact answer.

Using a t value of 10 years

Answer:

651558

Step-by-step explanation:

Given that:

Initial population, P0= 400,000

Growth rate, r = 5%

Using the relation :

P(t) = P0 * (1 + r)^t

t = number of years = 10

P(10) = 400000 * (1 + 0.05)^10

P(10) = 400000 * (1.05)^10

P(10) = 400000 * 1.628894626777

P(10) = 651557.8507

= 651558 nearest whole number.

Recall that, the t value used is hypothetical and should be replaces with te exact value given in your question.

7 0

2 years ago

What is the quotient for -20/-2?

Allisa [31]

The quotient is 10 :)

5 0

2 years ago

Read 2 more answers

What is the value of x? Idk plz help me

FrozenT [24]

The answer is 55 degrees

8 0

3 years ago