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2 years ago

The quotient of k decreased by 9 and 4 in symbol form

Mathematics

1 answer:

levacccp [35]2 years ago

3 0

Answer:

The answer is down below

Step-by-step explanation: k decreased by 4 is k - 4, so we write this as a fraction over 9.

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A line goes through the point (2, 4) and has a slope of 3/2. Which of the following points is also on the line? CHOOSE ALL THAT

Korolek [52]

Hmmmm not sure

Explanation: I took this test and got it correct

8 0

2 years ago

The net of a square pyramid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has

Neko [114]

Given:

The dimensions:

Square pyramid

Square base: 2x2

1 out of 4 triangles: 1/2x2x5

4 triangles: 2x2x5

To find:

The SURFACE AREA of the square pyramid

Find answer:

Step 1

Find the area of the square base -

Square base:

SA = L x W

= 2 x 2

= 4

The surface area of the square is 4 square inches

Step 2

Find the area of the 4 Triangles:

We will use a different formula here, to find 1 triangle, we will have to do:

$SA = \frac{1}{2} *B*H$

To find 2 triangles, we will do:

$SA = B*H$

But to find 4 triangles in just 1 step, we will do:

$SA=2*B*H$

Let's do it!

$SA = 2*2*5\\=2*10\\=20$

The surface area of the 4 triangles are 20 square inches

Step 3

Add answers to get FINAL ANSWER

Easy!

20+4=24

<h2>Hence, the Surface Area of the Square Pyramid is 24 square inches</h2>

4 0

1 year ago

Brian runs 3 miles in 25 minutes 30 seconds, and Mary runs 4 miles in 34

Katyanochek1 [597]

Answer:

Same speed.

Step-by-step explanation:

divide Distance by speed

25.5/3=8.5mph

34/4=8.5mph

4 0

3 years ago

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

4 0

2 years ago

Number 2 says Write the given equation in exponential form. Log8 1/512=-3

MA_775_DIABLO [31]

In exponential form it is given as, 8⁻³ = $$\frac{1}{512}$

Step-by-step explanation:

We have to write the given equation in the exponential form, that is in the form of base to the power value.

Given:

log₈ ( $$\frac{1}{512}$ ) = -3

Here the base is 8.

In the exponential form, it is written as,

base to the power 3 = 512

Here the reciprocal of 512 is given, so,

base to the power -3 = $$\frac{1}{512}$

So the exponential form is given as, 8⁻³ = $$\frac{1}{512}$

7 0

2 years ago