Answer:
Any set of (x , y) whose distance from (4, -3) is 3 units lies on the circle.
Step-by-step explanation:
To find the distance , use the formula
If distance < 3, (x, y) lies inside the circle.
If distance > 3, (x, y) lies outside the circle.
If distance = 3 (x, y) lies on the circle.
Answer:
50 miles per hour
Step-by-step explanation:
In this question, we are asked to substitute the information given into the equation. First we need consistency on units. Hence the 1hr 30 minutes is same as 1.5hrs
Now since d =rt
We need to get r = d/t
This means r = 75/1.5 = 50 miles per hour
Answer is 7
plug in 4 for x in the g(x) equation and get 3, plug in 2 for x in the h(x) equation and get -4. then, 3-(-4)=7 because two negatives equal a positive
Hello,
We know that if we make the same operation on both sides, we don't affect the equation:
For example:
Do you see? we add 2 on both sides and we don't affect the equality
We can do the same with the multiplication, for example
4=4 (i'll multiply both sides by 1/2)
Now, we do exactly the same in your excercise:
![P=2(L+W) \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[multiply\,\,by\,\,1/2] \\ \\ P*\bold{ \frac{1}{2}}=2(L+W)*\bold{ \frac{1}{2}} \\ \\ \frac{P}{2}=L+W\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,[Subtract\,\,L]\\ \\ \frac{P}{2}-\bold{L}=L+W-\bold{L}\\ \\ \frac{P}{2}-\bold{L}=L-\bold{L}+W \\ \\ \frac{P}{2}-L=W\\ \\ \boxed{ W= \frac{P}{2}-L }](https://tex.z-dn.net/?f=P%3D2%28L%2BW%29%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5Bmultiply%5C%2C%5C%2Cby%5C%2C%5C%2C1%2F2%5D%20%5C%5C%20%5C%5C%20P%2A%5Cbold%7B%20%5Cfrac%7B1%7D%7B2%7D%7D%3D2%28L%2BW%29%2A%5Cbold%7B%20%5Cfrac%7B1%7D%7B2%7D%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7BP%7D%7B2%7D%3DL%2BW%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5BSubtract%5C%2C%5C%2CL%5D%5C%5C%20%20%5C%5C%20%5Cfrac%7BP%7D%7B2%7D-%5Cbold%7BL%7D%3DL%2BW-%5Cbold%7BL%7D%5C%5C%20%20%5C%5C%20%5Cfrac%7BP%7D%7B2%7D-%5Cbold%7BL%7D%3DL-%5Cbold%7BL%7D%2BW%20%5C%5C%20%20%5C%5C%20%5Cfrac%7BP%7D%7B2%7D-L%3DW%5C%5C%20%5C%5C%20%5Cboxed%7B%20W%3D%20%5Cfrac%7BP%7D%7B2%7D-L%20%7D)
The diameter is equal to the radius multiplied by 2.
