Answer:
Hypotenuse = 14 inches
Adjacent = 12.12 inches
Step-by-step explanation:
Using SOH, CAH TOA Method
According to SOH
Sin(theta) = Opposite/Hypotenuse
Given theta = 30°
Opposite = 7 inches
Sin30° = 7/Hypotenuse
Hypotenuse = 7/Sin30°
Hypotenuse = 7/0.5
Hypotenuse = 14 inches
The other leg will be the adjacent saying x using Pythagoras Theorem to get x
Hypotenuse^2 = Opposite^2 + Adjacent^2
14^2 = 7^2 + x^2
x^2 = 14^2 - 7^2
x^2 = 196 - 49
x^2 = 147
x = sqrt of 147
x = 12.12 inches
Subtract 7 from both sides
x=-4
Answer:
Step-by-step explanation:
<h3>Q13</h3>
The greater the angle the greater the opposite side
<u>Sides in ascending order:</u>
- AB = 17, AC = 18, BC = 21
<u>Angles in same order</u>
<h3>Q14</h3>
<u>As above, sides in ascending order:</u>
- AB = 15, AC = 16, BC = 17
<u>Angles in same order</u>
<h3>Q15</h3>
<u>Exterior angle equals to sum of non-adjacent interior angles</u>
- 142° = x + 66°
- x = 142° - 66°
- x = 76°
<h3>Q16</h3>
<u>Same subject and isosceles triangle:</u>
- x + x = 158°
- 2x = 158°
- x = 79°
<h3>Q17</h3>
<u>Same subject</u>
- m∠QSR = m∠QPS + m∠PQS
- 2x = x + m∠PQS
- m∠PQS = 2x - x
- m∠PQS = x
ΔPQS has two angles with the measure of x, hence their opposite sides are congruent and the triangle is isosceles
There's a theorem for this: the angle made by two intersecting secants of a circle has a measure equal to half the difference of the arcs the secants intercept. In this case,
<em>x</em> = (130° - 30°) / 2 = 50°
The remainder of this polynomial is 1.
