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bagirrra123 [75]
3 years ago
7

Please answer, what is the solution of the system below? how do you know?

Mathematics
1 answer:
nydimaria [60]3 years ago
7 0

Answer:

(1,3)

Step-by-step explanation:

The solution is where the two lines intersect.

In this graph, it's (1,3)

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All fractions contain integers and rational numbers

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Answer:  Choice B) SAS

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Explanation:

The sides that have the double tickmarks are the same length. This forms one "S" of "SAS".

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The angle is between the two sides allowing us to use SAS. The order is important.

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Find the sum: |5| + (-3) + |-6| + 5.
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Which one is right. I am lost and I need help
Lubov Fominskaja [6]

Reflection across y=x is a special case transformation


(x,y) \rightarrow (y,x)


The original triangle has vertices A(-5,1), B(-4,3), C(-2,1), D(-3,-1) so the transformed triangle has vertices


A'(1,-5), B'(3,-4), C'(1,-2), D'(-1,-3)


Choice A'(1,-5)




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4 years ago
Given the function how do I solve
BARSIC [14]

Answer: (a) -7      (b) \bold{\dfrac{4}{25}}      (c) \bold{-\dfrac{5}{2}}    (d) 4

Step-by-step explanation:

A) f(x) = 2x - 3      when x is between -5 and -2 (including -5 and -2)

B) f(x) = x²            when x is between -2 and 2 (including 2)

C) f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}             when x is between 2 and 5 (including 5)

a) Equation A includes x = -2

   f(x) = 2x - 3

   f(-2) = 2(-2) - 3

           =  -4    - 3

           =       -7

b) Equation B includes x = -\dfrac{2}{5}

   f(x) = x²

   f\bigg(-\dfrac{2}{5}\bigg) = \bigg(-\dfrac{2}{5}\bigg)^2

        =\dfrac{4}{25}

c) Equation C includes x = 4

   f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}

   f(4)=-\dfrac{3}{2}(4)+\dfrac{7}{2}

       =-\dfrac{12}{2}+\dfrac{7}{2}

       =-\dfrac{5}{2}

d) Try each equation to see if x falls within the values given.

A) f(x) = 2x - 3

   -2.5 = 2x - 3

    0.5 = 2x

  0.25 = x    NOT VALID since x should be between -5 and -2

B) f(x) = x²

   -2.5 = x²

   \sqrt{-2.5}=x  NOT VALID since x cannot be an imaginary number

C) f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}

    -\dfrac{5}{2}=-\dfrac{3}{2}x+\dfrac{7}{2}

    -\dfrac{12}{2}=-\dfrac{3}{2}x

    -\dfrac{12}{2}\bigg(\dfrac{2}{3}\bigg)=x

    4 = x        VALID since x is between 2 and 5

5 0
4 years ago
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