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zhannawk [14.2K]
3 years ago
11

Hellllllllllllllp meeeeeeeeeeeeeee thank you

Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:  Choice B) SAS

=======================================================

Explanation:

The sides that have the double tickmarks are the same length. This forms one "S" of "SAS".

The square angles are 90 degree angles, or right angles. They are congruent. This forms the "A" of "SAS".

The overlapping sides are the same length, which forms the second "S" of "SAS".

The angle is between the two sides allowing us to use SAS. The order is important.

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You have a pet hamster and a pet mouse. The hamster weighs 416 of a pound. The mouse weighs 116 of a pound. How much more does t
Harrizon [31]

How much more does the hamster weighs than the mouse is 300 pounds.

Since we have a pet hamster and a pet mouse. We know that the hamster weighs 416 of a pound and the mouse weighs 116 of a pound.

To know how much more the hamster weighs more than the mouse, we take the difference between the weight of the hamster and the weight of the mouse.

Since the weight of the hamster = 416 pounds and the weight of the mouse equals 116 pounds.

<h3>The difference in weight</h3>

The difference in the weight d = weight of hamster - weight of mouse

= 416 pounds - 116 pounds

= 300 pounds.

So, how much more does the hamster weighs than the mouse is 300 pounds.

Learn more about difference here:

brainly.com/question/751620

4 0
3 years ago
64/7 as a mixed number
masya89 [10]
9 and 1/7
You can just look it up on the internet. 
6 0
3 years ago
Read 2 more answers
Find each quotient <br><br> 2/3 divided by 4/7<br><br> 1 5/6 divided by 5 2/5
pav-90 [236]

Answer:

\frac{55}{162}

1\frac{1}{6}

Step-by-step explanation:

1\frac{5}{6} \div 5\frac{2}{5} = \frac{11}{6} \times  \frac{5}{27} = \frac{55}{162} \\  \\  \frac{2}{3} \div \frac{4}{7} =  \frac{2}{3} \times \frac{7}{4} = \frac{14}{12} = \frac{7}{6} = 1\frac{1}{6}

I am joyous to assist you anytime.

6 0
3 years ago
Pre-image ABCD was dilated to produce image A'B'C'D' What is the scale factor from the pre-image to the image?
Greeley [361]

Answer:

The answer is 3/4

Step-by-step explanation:

4 0
3 years ago
Who can help me d e f thanks​
12345 [234]

d)

y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}

Product rule:

y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'

Chain and power rules:

y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'

Power rule:

y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)

Now simplify.

y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}

y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}

e)

y = \dfrac{3bx + ac}{\sqrt{ax}}

Quotient rule:

y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}

y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}

Power rule:

y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}

Now simplify.

y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}

y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}

y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}

f)

y = \sin^2(ax+b)

Chain rule:

y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'

y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'

y' = 2a \sin(ax+b) \cos(ax+b)

We can further simplify this to

y' = a \sin(2(ax+b))

using the double angle identity for sine.

7 0
2 years ago
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