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3 years ago

Solve five and three sixths minus two and one third.

Mathematics

1 answer:

CaHeK987 [17]3 years ago

4 0

Answer:

3 3/18

Step-by-step explanation:

5 3/6-2 1/3

We first need to turn our mixed numbers into fractions by multiplying the while number by the denominator, then adding the numerator. When we do this, 5 3/6 turns into 33/6 and 2 1/3 turns into 7/3. Now we have this:

33/6-7/3

Now we need to find the Least common multiple of the denominators in order to find our common denominator, which in this case is 6. 33/6 already has a denominator of 6, so we do not need to do anything to it. To give a denominator of 6 to 7/3, however, we must multiply by 2, giving us this:

33/6-14/6

Now we can subtract the numerators.

19/6

To turn this back into a mixed number, we divide 19 by 6, which gives us 3 with a remainder of 1. Therefore, our answer is 3 1/6. This is an equivalent fraction to the fourth answer, 3 3/18.

HTH :)

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Find the x- and y- intercepts of parabola y=5x^2-16x+10

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Y-INTERCEPT

$y = 5x^2 - 16x + 10$

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

$\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10$

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

$y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0$

We need to use the quadratic formula

The quadratic formula helps us find what values of $x$ make the equation = 0

Quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\$

The x-intercepts are at:

$(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)$

5 0

1 year ago

Suatu jenis roti memerlukan 150 gram tepung dan 50 gram mentega. Roti jenis lain memerlukan 75 gram tepung dan 75 gram mentega,

Katena32 [7]

Let the one type of the bread be bread A
The second type of the bread be bread B

Let the flour be 'f' and the butter be 'b'

We need 150f + 50b for bread A and 75f + 75b for bread B

We can compare the amount of flour and bread needed for each bread and write them as ratio

FLOUR

Bread A : Bread B
150 : 75
2 : 1

We have a total of 2250gr of flour, and this amount is to be divided into the ratio of 2 parts : 1 part. There is a total of 3 parts.

2250 ÷ 3 = 750 gr for one part then multiply back into the ratio to get

Bread A : Bread B = (2×750) : (1×750) = 1500 : 750

BUTTER

Bread A : Bread B = 50 : 75 = 2 : 3

The amount of butter available, 1250 gr is to be divided into 2 parts : 3 parts.
There are 5 parts in total

1250 ÷ 5 = 250 gr for one part, then multiply this back into the ratio

Bread A: Bread B = (2×250) : (3×250) = 500 : 750

Hence, for bread A we need 1500 gr of flour and 500 gr of butter, and for bread B, we need 750 gr of flour and 750 gr of butter.

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2 years ago

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|v|>3 solution to the inequality on the number line

Andrew [12]

On a number line, v would be all the numbers to the left of -3 (for example, |-4|=4 which is greater than 3) and all the values to the right of positive 3. Since it can't equal 3, v=-3 and v=3 are not included on the number line.

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3 years ago

Which of the following does not satisfy the inequality 3(x + 4) − x > 4?

stealth61 [152]

Answer:

Step-by-step explanation: It's B because -4 isn't greater than -4 it is the same number, and the symbol isn't greater than or equal to it is just greater than. Your answer is B.

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2 years ago

What is the value of the expression z-4/-8 when z = –28?

Alexeev081 [22]

Hello,

(-28-4)/(-8)=-32/(-8)4

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