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Nikolay [14]
2 years ago
11

Uncle Eddie asked Mckenna and Lara to order 46 new wheels for 18 skateboards and bicycles in his repair shop. How many bicycles

and how many skateboards are in Uncle Eddie’s shop?
Mathematics
1 answer:
OverLord2011 [107]2 years ago
3 0

Answer:

The Correct Answer is: <em>15 bicycles and 6 skateboards.</em>

Step-by-step explanation:

I'm sure it is that one. No Doubts.

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Five observations taken for two variables follow.
I am Lyosha [343]

Answer:

a) Figure attached

b) If we see the scatter plot we can conclude that the possible relation between x and y is linear and with a positive correlation since when the values of x increases the values for y increases as well.

c) Cov (X,Y) = \frac{\sum_{i=1}^n (x_i -\bar X)(y_i -\bar Y)}{n-1}

We can find the numerator like this:

\sum_{i=1}^5 (6-16)(6-10)+(11-16)(9-10)+(15-16)(6-10)+(21-16)(17-10)+(27-16)(12-10)=106

And then:

Cov(X,Y) = \frac{106}{5-1}=26.5

d) r=\frac{5(906)-(80)(50)}{\sqrt{[5(1552) -(80)^2][5(586) -(50)^2]}}=0.693  

Step-by-step explanation:

Part a

For this part we use excel in order to create the scatterplot and we got the result on the figure attached.

Part b

If we see the scatter plot we can conclude that the possible relation between x and y is linear and with a positive correlation since when the values of x increases the values for y increases as well.

Part c

The sample covariance is defined as:

Cov (X,Y) = \frac{\sum_{i=1}^n (x_i -\bar X)(y_i -\bar Y)}{n-1}

We can find the numerator like this:

\sum_{i=1}^5 (6-16)(6-10)+(11-16)(9-10)+(15-16)(6-10)+(21-16)(17-10)+(27-16)(12-10)=106

And then:

Cov(X,Y) = \frac{106}{5-1}=26.5

Part d

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=5 \sum x = 80, \sum y = 50, \sum xy = 906, \sum x^2 =1552, \sum y^2 =586  

r=\frac{5(906)-(80)(50)}{\sqrt{[5(1552) -(80)^2][5(586) -(50)^2]}}=0.693  

So then the correlation coefficient would be r =0.693

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