1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Georgia [21]
2 years ago
10

Write an equation to represent the number of pages Jesse has read. Using x, the number of days Amir has been reading, write an e

xpression to represent the number of days Jesse has been reading. Remember that Jesse started reading one day before Amir. Use this expression to write an equation for the number of pages Jesse has read. Let y represent the number of pages read.
Mathematics
1 answer:
katrin [286]2 years ago
7 0

Question:

Jesse and Amir were assigned the same book to read. Jesse started reading on Saturday, and he is reading 30 pages a day. Amir didn't start until Sunday, but he is reading 35 pages a day.

How many days will it take Amir to catch up to Jesse, and how many pages will they each have read?

Write an equation to represent the number of pages Amir has read. Use x to represent the number of days Amir has been reading and y to represent the number of pages he has read.

Answer:

It will take 6 days

Step-by-step explanation:

For Jesse:

Rate = 30\ pages/day

This implies that Jesse will cover 30y in y days

For Amir:

Rate = 35\ pages/day

This implies that Amir will cover 35x in x days

Because Amir starts a day later,

y = x + 1

So, we have the following equations:

Jesse = 30y

Amir= 35x

y = x + 1

To get the number of days when they read the same number of pages, we have:

Jesse = Amir

Substitute values for Jesse and Amir

30y = 35x

Substitute x + 1 for y

30(x+1) = 35x

Open bracket

30x+30 = 35x

Collect Like Terms

30 = 35x-30x

30 = 5x

Solve for x

\frac{30}{5} = \frac{5x}{5}

\frac{30}{5} = x

6 = x

x = 6

You might be interested in
What is the percentage decrease if an item has dropped from $115 to $46
Sav [38]

Answer: 60% decrease

Step-by-step explanation:

Look at the attachment

4 0
3 years ago
What is an equation of the line that is perpendicular to y=−23x+5 and passes through the point (2, 11) ?
hichkok12 [17]

Answer:

The equation would be y = 1/23x - 251/23

Step-by-step explanation:

To start, you need to locate the slope of the first equation. Since the slope is the coefficient of x, we know it to be -23. Now, the perpendicular slope is the opposite and reciprocal of that, which makes the new slope 1/23.

Now that we have this, we can use the point and the slope in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 11 = 1/23(x - 2)

y - 11 = 1/23x - 2/23

y = 1/23x - 251/23

5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLY PLEASE HELPPPPP
erica [24]

Answer:

C

Step-by-step explanation:

4(8-x)=8

32-4x=8

-4x=-24

x=6

5 0
3 years ago
Read 2 more answers
You run out of gas and measure the amount of gas it takes to fill the tank. Is this data a type discrete or continuous
ziro4ka [17]

I think it is continuous

7 0
3 years ago
Thissss please‍♀️ AND THANK YOUUU
3241004551 [841]

Answer:

5*5*5*5 = 625

3*3*3*3*3*3 = 729

5 0
3 years ago
Other questions:
  • Solve the equation and graph the solution:<br><br>24 + 6k &lt; -6(-4-k) <br>​
    12·1 answer
  • Evaluate the expression when a=-7. a^2+4a-2
    11·1 answer
  • Fill in the blank with &gt;,&lt;, or =: 2.5 ___ 2.45
    8·2 answers
  • PLZ HELP MEEE !!!!!!!!!!
    8·2 answers
  • Find the value of x in the triangle shown below.<br>​
    12·1 answer
  • Me ayudan por favor ??? thank youu
    13·1 answer
  • Students in an Introductory Statistics class at BYU-Idaho were studying prices of cold cereal at grocery stores in Rexburg. To g
    10·1 answer
  • What is the GFC 3x^2-9x-120
    7·1 answer
  • Please help me, if you help then thanks!
    14·1 answer
  • the usda reported that in 1990 each person in the united states consumed an average of 133 pounds of natural sweeteners. they al
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!