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Pachacha [2.7K]
3 years ago
11

Plzzzzzzzzzzzzzzzz help me I’ll mark you brainlist

Mathematics
2 answers:
marissa [1.9K]3 years ago
5 0

Answer:

Ewan?1234567891011121314151617181920

mixas84 [53]3 years ago
5 0

Answer:

No clue at all. ?

Step-by-step explanation:

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What the hell is The opposite of 1
alexira [117]

Answer: -1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How do I figure this anser-6w < 84​
Sophie [7]

Answer:

w > -14

Step-by-step explanation:

Divide both sides by -6.

-6w/-6 = w

84/-6 = 14

Since it's an equality, if the coefficient of the variable is negative, when you divide the sign flips to the opposite.

4 0
3 years ago
A quadrilateral can be inscribed in a circle, if and only if, the opposite angles in that quadrilateral are supplementary.
Setler [38]

The opposite angles are equal to are supplementary to each other or equal to each other.

<h3>What is a Quadrilateral Inscribed in a Circle?</h3>

In geometry, a quadrilateral inscribed in a circle, also known as a cyclic quadrilateral or chordal quadrilateral, is a quadrilateral with four vertices on the circumference of a circle. In a quadrilateral inscribed circle, the four sides of the quadrilateral are the chords of the circle.

The opposite angles in a cyclic quadrilateral are supplementary. i.e., the sum of the opposite angles is equal to 180˚.

If e, f, g, and h are the inscribed quadrilateral’s internal angles, then

e + f = 180˚ and g + h = 180˚

by theorem the central angle = 2 x inscribed angle.

∠COD = 2∠CBD

∠COD = 2b

∠COD = 2 ∠CAD

∠COD = 2a

now,

∠COD + reflex ∠COD = 360°

2e + 2f = 360°

2(e + f) =360°

e + f = 180°.

Learn more about this concept here:

brainly.com/question/16611641

#SPJ1

6 0
2 years ago
At the Sunnyvale Play House, the price for an adult ticket is $12 and the price of a child's ticket is $6. For Saturday night's
Rzqust [24]

Answer:

a + c = 125 & 12a + 6c = 1140

Step-by-step explanation:

adult ticket total + child ticket total = 125 total tickets

($12 x adult ticket total) + ($6 x child ticket total) = $1140

4 0
3 years ago
Before sending track and field athletes to the Olympics, the U.S. Holds a qualifying meet. The box plots below show the distance
sleet_krkn [62]

Question:

The options are;

A. The distances in the Olympic final were farther on average.

B. The distances in the Olympic final varied noticeably more than the US qualifier distances

C. The distances in the Olympic final were all greater than the US qualifier distances

D. none of the above

Answer:

The correct option is;

A. The distances in the Olympic final were farther on average.

Step-by-step explanation:

From the options given, we have

A. The distances in the Olympic final were farther on average.

This is true as the sum of the 5 points divided by 5 is more in the Olympic final

B. The distances in the Olympic final varied noticeably more than the US qualifier distances

This is not correct as the difference between the upper and lower quartile in the Olympic final is lesser than in the qualifier

C. The distances in the Olympic final were all greater than the US qualifier distances

This is not correct as the max of the qualifier is more than the lower quartile in the Olympic final

D. none of the above

We have seen a possible correct option in option A

7 0
3 years ago
Read 2 more answers
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