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balandron [24]
3 years ago
12

Estimate the area of the rectangle. A)8 B)10 C)14 D)20

Mathematics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

A or B, I think it's A...

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Please solve thanks!
Alona [7]

Answer:

f(-3)=4

b

Step-by-step explanation:

lol is this edgenuity

7 0
3 years ago
y=-2x-7.A new path will be built perpendicular to this path. The paths will intersect at the point(-2,-3). Identify the equation
Over [174]

Answer:

y=1/2 x -2 is the perpendicular line equation

Step-by-step explanation:

y=1/2 x + b

solving for b:

-3=-1 +b

b==- 3+1 = -2

5 0
3 years ago
Find the dimensions of the rectangle with maximum area that can be inscribed in a circle of radius 10.
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

That will be a square with a diagonal of 20

side length of 20sin45

and area of (20sin45)² = 200 units²

prove it you say?

Area of a rectangle is base times height

A = bh

With a radius of 10, the diagonals of any rectangle inscribed will be 20 units

20² = b² + h²

h = \sqrt{400 - b^2}

A = bh

A = b\sqrt{400 - b^2}

Area will be maximized when the derivative is set to zero

           dA/db = \sqrt{400 - b^2} - b²/ \sqrt{400 - b^2}

                   0 = \sqrt{400 - b^2} - b²/ \sqrt{400 - b^2}

b²/\sqrt{400 - b^2} =  \sqrt{400 - b^2}

                  b² = 400 - b²

                2b² = 400

                  b² = 200

                  b = \sqrt{200}

h = \sqrt{400 - b^2}

h = \sqrt{400 - \sqrt{200}^2 }

h = \sqrt{200}

A = bh

A =  \sqrt{200}•\sqrt{200}

A = 200 units²

5 0
3 years ago
Round to the nearest whole number. Simplify (5(12 - 2)2 + 7]/3=
mario62 [17]

(5(12-2)2+7)/3

(5(10)2+7)/3

(50(2)+7)/3

(100+7)/3

107/3

35.66666...

<h2><em>36</em></h2>
7 0
3 years ago
Find the product using the FOIL method.<br> (q-2)(q-8)
galina1969 [7]
Q^2-2q-8q+16
=q^2-10q+16
6 0
3 years ago
Read 2 more answers
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