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KATRIN_1 [288]
3 years ago
7

Jose is baking cakes. He needs 3/4 of butter for each cake. One stick of butter is a 1/2 of a cup. How many sticks do he need to

bake 8 cakes?
Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

Answer: 6 sticks

Step-by-step explanation:

Given

Joe needs \frac{3}{4} butter for each cake

One stick of butter is equivalent to 0.5 cup

So, joe need

\dfrac{3}{4}\times \dfrac{1}{2}=\dfrac{3}{8}\ \text{cup}

for each cake

To bake 8 cakes, it is

\Rightarrow \dfrac{3}{4}\times 8=6\ \text{sticks}

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5 less the quotient of 14 times a number x and 9
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Answer:

\frac{14x}{9}-5

Step-by-step explanation:

14 times a number x :  14* x = 14x

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Help me plz I need help
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Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

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let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
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