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rewona [7]
3 years ago
7

X2 - 4x + ______________________

Mathematics
2 answers:
denpristay [2]3 years ago
8 0
The answer to this question is 4
diamong [38]3 years ago
6 0

Answer:

4

Step-by-step explanation:

You would complete the square by dividing the b value by 2, and then squaring it. In this case, the b value is -4. You would divide -4 by 2 and get -2. Now, you would square -2, and you would get 4.

You might be interested in
(a) Complete the table of values for the graph x + y = 6
djyliett [7]

Answer:

(0,6)

(1,5)

(2,4)

(3,3)

(4,2)

Step-by-step explanation:

To solve this table first convert the equation to slope-intercept form (y=mx+b), to do this solve for y in the equation. The slope-intercept form is y=-x+6, where -1 is the slope and 6 is the y-intercept. Then from that, you can get your first point, because you know the y-intercept is 6, therefore when x equals 0 y must be 6. Next, because the slope is -1 that means the y-value decreases by 1 every time the x-value increases by 1. So to find the rest of the y-values simply subtract 1 from the previous y-value.

4 0
3 years ago
9 1/4 + x = 2 3/8 express the solution as a fraction or mixed number in simplest form
Verdich [7]

Answer:

X= -6 7/8

Step-by-step explanation:

(9 1/4) + (-6 7/8)= 2 3/8

4 0
3 years ago
Read 2 more answers
1. Solve: 9^2x + 1 = 9^3x – 2
katovenus [111]

Answer:

c

Step-by-step explanation:

my dads friend died ;-;

4 0
3 years ago
Read 2 more answers
PLEASE HELP WILL MARK BRAINLIEST❗️❗️❗️❗️❗️
Sonja [21]

Answer:

x = 24

Step-by-step explanation:

x^2 + 7^2 = (x+1)^2

x^2 + 49 = x^2 + 2x + 1

x^2 - x2 = 0

49 - 1 = 2x

48/2 = x

x = 24

4 0
3 years ago
I need help in partial fraction!! With simple explaination would be nice!
WITCHER [35]
\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}

Now the second term can be decomposed into partial fractions.

\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}
\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}
4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)
4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1
\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3
\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}

So

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}

3 0
3 years ago
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