The equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 1
<h3>Equation of a line</h3>
A line is the distance between two points
Given the equation of a line expressed as 10x + 2y = -2. Determine the slope
2y = -10x -2
y = -5x - 1
Slope of the line is -5
The equation of a line in point-slope form is y - y1 = m(x-x1)
Substitute the point and the slope of the parallel line
y - 12 = -5(x - 0)
y - 12 = -5x
y = -5x + 12
Hence the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 12
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Answer:
x = 4(y + 6)/5
Step-by-step explanation:
2x - y = (3/4)x + 6
2x - (3/4)x = y + 6
(8x - 3x)/4 = y + 6
5x/4 = y + 6
5x = 4(y + 6)
5x = 4y + 24
x = (4y + 24)/5
Therefore, x = 4(y + 6)/5
122 with 58
35 with 145
62 with 118
105 with 75
Your answer is -2 as the axis of symmetry is at -b/2a. So if you were to expand the equation, you would get y= x^2/4 +x -6 where b is 1 and 2a is ½ . Therefore -1 / ½ gives you -2
