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dem82 [27]
2 years ago
11

Colin gets pic 'n mix when at the cinema and makes his bag up with 3 types of sweet. He pick:

Mathematics
1 answer:
Kisachek [45]2 years ago
4 0

Answer: 2/3

Explanation: Assume that the number of smarties he picked is c.

Now, we are given that:

1- He picked 3 times as many cola bottles as smarties. This means that:

Number of cola bottles he picked = 3s

2- He picked twice as many smarties as marshmallows. This means that:

number of marshmallows he picked = 0.5s

Now to get the proportion o f cola bottles, we will divide the number of cola bottles by the total number of sweets as follows:

proportion of cola bottles =  

Hope this helps :)

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Solve for x: 4(x + 2) = 3(x − 2)<br><br>A) −2<br>B)−4<br>C) −10<br>D) −14
BARSIC [14]

4(x+2)=3(x-2)

Multiply the first bracket by 4

Multiply the second bracket by 3

4x+8=3x-6

Move 3x to the left hand side, whenever moving a number with a letter the sign changes ( positive 3x to negative 3x)

4x-3x+8=3x-3x-6

x+8=-6

Move positive 8 to the right hand side

x+8-8=-6-8

x=-14

Check answer by using substitution method

Use x=-14 into both of the equations

4(-14+2)=3(-14-2)

-56+8=-42-6

-48=-48

Answer is -14- D)

6 0
3 years ago
What does it mean to solve an equation?
Ivanshal [37]
To add, subtract, multiply or divide the number given to get a whole number or an integer
4 0
3 years ago
Use the distributive property to simplify the following expression: 3y(2 - y) + 8y
Debora [2.8K]
3y(2 - y) + 8y
6y - 3y^2 + 8y
-3y^2 + 14 y
5 0
3 years ago
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
A recipe needs 4/5 cups of butter for every 2 cups of flour. If you plan to use 3 cups of flour, how much butter will you need?
DedPeter [7]

Answer:

1 1/5 cups of butter

Step-by-step explanation:

4/5=2

      =3

 4/5 x 3=12/5

12/5 / 2

12/5 x 1/2=1 1/5

7 0
3 years ago
Read 2 more answers
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