You multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get 3x^2y
equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)
Perpendicular bisector lies at the midpoint of a line
Lets find mid point of (-9,-8) and (7,-4)
midpoint formula is


midpoint is (-1, -6)
Now find the slope of the given line
(-9,-8) and (7,-4)


Slope of perpendicular line is negative reciprocal of slope of given line
So slope of perpendicular line is -4
slope = -4 and midpoint is (-1,-6)
y - y1 = m(x-x1)
y - (-6) = -4(x-(-1))
y + 6 = -4(x+1)
y + 6 = -4x -4
Subtract 6 on both sides
y = -4x -4-6
y= -4x -10
equation for the perpendicular Bisector y = -4x - 10
Answer:
-4,-2,-1
Step-by-step explanation:
The next term is going to be the previous number divided by two
Answer:
The Answer is -x + 3.
Step-by-step explanation:
It's honestly one of the longest process'. Above is the right answer though. Hope it helped.