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stepladder [879]
3 years ago
7

Why is radian measure used in Geometry?

Mathematics
1 answer:
Vladimir [108]3 years ago
3 0
The infinite series description of trig functions is much neater when the argument is radians. For example, for small angles, sin(x) ≈ x when x is in radians. You could say that radians is the "natural" measurement unit for angles, just as "e" is the "natural" base of logarithms.

If the angle measure were degrees or grads or arcseconds, obnoxious scale factors would show up everywhere.
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Error Analysis jessie incorrectly said the rate 1/5 hour 1/10 acer can be written as the unit rate 1/50 per acer . What is the c
vodka [1.7K]

Answer:

2

Step-by-step explanation:

Jessie multiplied instead of dividing. That’s why she gets 1/50

she should have divided

when we divide we get the answer 2

4 0
3 years ago
Read 2 more answers
The length of a rectangle is twice its width. if the area of the rectangle is 128 ft2 , find its perimeter.
kupik [55]
Length(l)= 2w
Width(w)= w
Area(A) = l*w

A= 128 ft²
128= l*w
128= (2w)w
2w²= 128
w²= 64
w=√64= 8 ft
w= 8 ft

length(l)= 2w
l=2(8)
l=16 ft

P= 2l+2w
P=2(16)+2(8)= 32+16= 48ft
P= 48ft

Answer:
The Perimeter of this rectangle is 48 feet.


Leave any questions you still have in the comments below please! Thank you! Hope this helped! :)
5 0
3 years ago
Helppp plsssss!!Thanks
OlgaM077 [116]

f(x) + g(x) =

                  4x + 3  

       3x^2 + 2x - 4

----------------------------------

    3x^      +6x     -1


Answer:   3x^      +6x     -1


Either you typed something wrong in the problem or the answer

3 0
3 years ago
Write the equation of a line that is parallel to the line 2x - 3y = 5 and passes through the point (2, -1)
jek_recluse [69]

Answer:

The equation of the line is 2x - 3y = 7 ⇒ answer A

Step-by-step explanation:

* Lets revise the relation between the parallel lines

- If two lines are equal then their slopes are equal

- We can make an equation of a line by using its slope and

 a point on the line

- If the slope of the line is m and passing through the point (x1 , y1),

 then we can use this form [y - y1]/[x - x1] = m to find the equation

* Lets solve the problem

- The line is parallel to the line 2x - 3y = 5

∴ the slope of the line = the slope of the line 2x - 3y = 5

- Rearrange the terms of the equation to be in the form

  y = mx + c to find the slope of it

∵ 2x - 3y = 5 ⇒ subtract 2x from both sides

∴ -3y = 5 - 2x ⇒ divide two sides by -3

∴ y = 5/-3 - 2x/-3 ⇒ y = 2/3 x - 5/3

∴ The slop of the line is 2/3

∵ The line passes through point (2 , -1)

* Lets use the rule to find the equation of the line

∵ y - (-1)/x - 2 = 2/3

∴ y + 1/x - 2 = 2/3 ⇒ by using cross multiplication

∴ 3(y + 1) = 2(x - 2) ⇒ open the brackets

∴ 3y + 3 = 2x - 4 ⇒ put x an d y in one side

∴ 2x - 3y = 3 + 4

∴ 2x - 3y = 7

* The equation of the line is 2x - 3y = 7

8 0
3 years ago
A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere  =\frac{2}{3}\pi r^3

Volume of a Cylinder =\pi r^2 h

Therefore:

The Volume of the Solid formed

=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Area of the Hemisphere =2\pi r^2

Curved Surface Area of the Cylinder =2\pi rh

Total Surface Area=

2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh

Cost of the Hemispherical Ends  = 2 X  Cost of the surface area of the sides.

Therefore total Cost, C

=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh

Recall: h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Therefore:

C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

C^{'}=\frac{-27840+32\pi r^3}{3r^2}

When \:C^{'}=0

-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518

Recall:

h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0
3 years ago
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