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dybincka [34]
4 years ago
14

A technique used to rewrite a quadratic function in standard form to vertex form is

Mathematics
1 answer:
BabaBlast [244]4 years ago
8 0
The vertex form of a quadratic function <span>is given by
                                      </span>f(x)=a(x-h)^{2}+k,
where (h,k) is the vertex of parabola. In some literatures, the standard form of the quadratic equation is written as 
                                     f(x)=a x^{2} +bx+c 
Therefore, in order to avoid the confusion, the first equation is taken as a vertex form. When the standard form is converted into the vertex form, the process is called completing the square. 
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Maya and Aimee compare the fractions 2/3 and 3//5. Their work is shown below.
White raven [17]

Answer:

Maya is correct. She wrote equivalent fractions with the same denominator and then correctly compared the fractions. Aimee wrote equivalent fractions with the same numerator but did not correctly compare the fractions. Only Maya is correct.

When you're comparing fractions, you have to set them equal to the same denominator, not the same numerator.

Hope this helps

5 0
2 years ago
Help!!! f(x)=x+3 g(x) =7x+4
allsm [11]

Answer:

8x+7

Step-by-step explanation:

5 0
3 years ago
Help
Flauer [41]
A) Measure of Angle L is 67.5. Angle F & Angle L are alternate interior angles.

b) Measure of Angle E is 112.5, because we know that F and H are vertical angles, so therefore they’re congruent. We also know H and E are adjacent, so H + E = 180.

c) Angles E and K are alternate exterior angles. Measure of Angle K is 112.5.

d) Measure of Angle H is 67.5, because we know that Angle F, which is vertical to Angle H, is 67.5. Vertical angles are congruent.

e) Measure of Angle I is 112.5, because Angle I and Angle K are vertical angles.

f) They’re corresponding angles.
3 0
2 years ago
How many permutations are possible for 13 objects taken 6 at a time?
Anarel [89]

Answer:

  1,235,520

Step-by-step explanation:

13P6 = 13!/(13-6)! = 13·12·11·10·9·8 = 1,235,520

__

There are 13 ways to choose the first object, 12 ways to choose the second, 11 ways to choose the third, and so on. The 6th object can be chosen 8 ways.

The total number of permutations is the product of all these ways:

  13·12·11·10·9·8 = 1,235,520

7 0
3 years ago
What is equivalent to the ratio 5/13
Rudik [331]
10/26, you can just multiply each number in the fraction by 2 :)
4 0
3 years ago
Read 2 more answers
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