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3 years ago

Solve the following inequality for x.

Mathematics

2 answers:

Alexus [3.1K]3 years ago

8 0

Answer:

X < -1

Step-by-step explanation:

4x - 5 + X < -10

5x < -5

× < -1

Y_Kistochka [10]3 years ago

7 0

Answer:

x<-1

Step-by-step explanation:

4x-5+x<-10

5x-5<-10

5x<-10+5

5x<-5

x<-5/5

x<-1

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Twelve large bottles of water cost $9.How many bottles can you buy for $3?

Andrej [43]

Answer: 4 large bottles of water for $3.

Step-by-step explanation: To find how many large water bottles you can buy with $3, you’ll have to divide 12 by 3 which equals to 4. You can check your answer by multiplying 4 x 3 which equals to 12, which is the original amount of large water bottles you can buy for $9.

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3 years ago

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

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3 years ago

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den301095 [7]

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Sorry I Don't Speak Spanish That Good

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3 years ago

Quadrilateral ABCD is a square with diagonals that intersect at point E. Find angle ADB. A. 11.25º B. 22.5º C. 45º D. 90º

never [62]

IT WOULD BE "D" I BELIEVE

HOPE IM RIGHT AND THIS HELPS

7 0

3 years ago

Read 2 more answers

The length of time, y hours, it takes to put a jigsaw puzzle together is inversely proportional to the number of children, x, wo

andrew11 [14]

Answer:

24 children

Step-by-step explanation:

If the length of time, y hours, it takes to put a jigsaw puzzle together is inversely proportional to the number of children, x, this is represented as;

$y \alpha \frac{1}{x}\\y =\frac{k}{x}$

k is the constant of proportionality

If it takes 16 children 6 hours to put the jigsaw puzzle together, this means at x = 16, y = 6

Substitute:

6 = k/16

k = 6*16

k = 96

W are to find number of children needed to put the same jigsaw puzzle together in 4 hours, this is done by substituting k = 96 and y = 4 into the expression y = k/x

y = 96/4

y = 24

Hence it will take 24 children to put the same jigsaw puzzle together in 4 hours

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3 years ago