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3 years ago

7x+3+6x+11 can u give a example of how to solve it

2 answers:

8 0

Ok, so the first thing you should do is collect like-terms.

7x+3+6x+11

Combine 7x and 6x ---> You'll get 13x.

So it'll be 13x + 3 + 11

Now you'll combine 3 + 11 and you'll get 14.

The answer should be 13x + 14

I hope this helped ^^*

yKpoI14uk [10]3 years ago

7 0

Combine like terms.

Since 7x and 6x both have a variable of x, you can combine them.

$7x + 6x = 13x$

After that, you are left with:

$13x + 11 + 3$

You also have two numbers without variables; 11 and 3. You can also combine those.

$11 + 3 = 14$

So, your final answer would be:

$13x + 14$

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Consider the $n$ th partial sum, denoted by $S_n$ :

$S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n$

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$\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}$

Subtract $S_n$ from this:

$\dfrac34S_n-S_n=\dfrac1{16}\left(\dfrac34\right)^{n+1}-\dfrac1{16}\left(\dfrac34\right)$

Solve for $S_n$ :

$-\dfrac14S_n=\dfrac3{64}\left(\left(\dfrac34\right)^n-1\right)$

$S_n=\dfrac3{16}\left(1-\left(\dfrac34\right)^n\right)$

Now as $n\to\infty$ , the exponential term will converge to 0, since $r^n\to0$ if $0$ . This leaves us with

$\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{k=1}^n\frac{3^k}{4^{k+2}}=\sum_{k=1}^\infty\frac{3^k}{4^{k+2}}=\frac3{16}$

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Talja [164]

Answer:

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Step-by-step explanation:

Let the cost of one steak dinners be x

Let the cost of one grilled salmon be y

One a particular day the waitress sells 12 ribeye steak dinners and 39 grilled salmon for a total is $575.53 which can be written in equation as

12(x)+39(y)= $575.53-------------------------------------(1)

On another day she sells 25 ribeye steak dinners and 13 grilled salmon dinners totals to $582.43.This can be represented as

25(x)+ 13(y)= $582.43-------------------------------------(2)

solving the equation (1) and (2)

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Subtracting these equation we get,

$113x=1171.76$

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7 0

3 years ago

The answer to this problem

horrorfan [7]

Work backwards with pythagoras' theorem:
c^2=a^2+b^2
Here, a and b both equal to x. Therefore, you can write this as 8^2=2x^2. So 64=2x^2. Sqrt on both sides to give you 8=2x, hence x=4. However I must warn you that this working out may have a flaw, as I found that x actually equals to 5.66

7 0

3 years ago