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3 years ago

Which of these strategies would eliminate a variable in system of equations?

Mathematics

1 answer:

Blababa [14]3 years ago

7 0

Answer: (b) Multiply the top equation by 3, multiply the bottom equation by 2, then add the equations.

Step-by-step explanation: the strat would eliminate a variable in this system

You might be interested in

1) Function B: x -> /5 -> +1 = y

GalinKa [24]

Answer:

Suppose f and g are two functions such that

1. (g ◦ f)(x) = x for all x in the domain of f and

2. (f ◦ g)(x) = x for all x in the domain of g

then f and g are said to be inverses of each other. The functions f and g are said to be

invertible.

. Properties of Inverse Functions: Suppose f and g are inverse functions.

• The rangea of f is the domain of g and the domain of f is the range of g

• f(a) = b if and only if g(b) = a

• (a, b) is on the graph of f if and only if (b, a) is on the graph of g

Step-by-step explanation:

7 0

4 years ago

If sin A= 0.8, find the positive value of cos A

Ahat [919]

Answer:

cosA = 0.6

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract sin²A from both sides )

cos²A = 1 - sin²A ( take the square root of both sides )

cosA = ± $\sqrt{1-sin^2A$

Since only the positive value is required , then

cosA = $\sqrt{1-(0.8)^2}$

= $\sqrt{1-0.64}$

= $\sqrt{0.36}$

= 0.6

6 0

3 years ago

Read 2 more answers

I need to sketch a graph for each line.<br> y = 4x-5<br><br> How would I solve and graph this

PtichkaEL [24]

So you need to find the slope and the y- intercept. So, the slope is always the coefficient on the x. In this case it is 4. The y-intercept is the other number. In this case it is -5. So the slope is 4 and the y-intercept is -5. On your graph (the y axis) find -5. Then you go up 4 and to the right 1 because of four were a fraction it would be 4/1. Keep going up four and right one a couple times. Then reverse it. Go down 4 left 1. That as a fraction would look like -4/-1. Then connect your points and make it a line!

4 0

3 years ago

Simplify <br> cosx ( tanx+cotx)

Soloha48 [4]

The first step to solving this is to use tan(t) = $\frac{sin(t)}{cos(t)}$ to transform this expression.
cos(x) × $( \frac{sin(x)}{cos(x)} + cot(x) )$
Using cot(t) = $\frac{cos(x)}{sin(x)}$ ,, transform the expression again.
cos(x) × $( \frac{sin(x)}{cos(x)} + \frac{cos(x)}{sin(x)} )$
Next you need to write all numerators above the least common denominator (cos(x)sin(x)).
cos(x) × $\frac{sin(x)^{2} + cos(x)^{2} }{cos(x)sin(x)}$
Using sin(t)² + cos(t)² = 1,, simplify the expression.
cos(x) × $\frac{1}{cos(x)sin(x)}$
Reduce the expression with cos(x).
$\frac{1}{sin(x)}$
Lastly,, use $\frac{1}{sin(t)}$ = csc(t) to transform the expression and find your final answer.
csc(x)
This means that the final answer to this expression is csc(x).
Let me know if you have any further questions.
:)

4 0

3 years ago

The function g(t)=−16t2+vt+h represents the height of an object, g, in feet, above the ground in relation to the time, t, in sec

kow [346]

Answer:

A) g(t) = - 16*t² + 80*t

B) domain is ( 0 ≤ t ≤ 5 )

Step-by-step explanation:

A) for the model rocket

h = 0 and v = 80 feet/sec

Then the equation g(t) = -16*t² + v*t + h

became

g(t) = - 16*t² + 80*t + 0 g(t) = - 16*t² + 80*t

B) The equation g(t) = - 16*t² + 80*t is defined for all real numbers then the domain interval for t is ( -∞ , ∞ ). Now in our case, a model rocket was launched is not possible to get negative values for g(t) then the biggest value for t = 5 from

-16*t² + 80*t ≥ 0

-16*t ≥ -80 16*t ≤ 80

t ≤ 5

And the domain is ( 0 ≤ t ≤ 5 )

8 0

3 years ago