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Alchen [17]
3 years ago
13

What is the perimeter, P, of a rectangle that has a length of x + 5 and a width of y − 1?

Mathematics
1 answer:
Helen [10]3 years ago
6 0

Answer:P=2x + 2y + 8

Step-by-step explanation: Perimeter (p) =2L+ 2w

P= 2(x+5)+2(y-1)

Remove bracket

P=2x+ 10 +2y - 2

P=2x+2y+8

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Sup yall<br><br> solve 4p-7r=pq+16 for p
kykrilka [37]

Answer:

p = (7r+16) / (4-q)

Step-by-step explanation:

4p - 7r = pq + 16

Add 7r to both sides.

4p = pq + 16 + 7r

Subtract pq from both sides.

4p - pq = 7r + 16

Factor out p from the left side.

p(4 - q) = 7r + 16

Divide both sides by (4 - q).

p = (7r + 16)/(4 - q)

The 7r and the 16 could be in either order, like 7r+16 or 16+7r. You could show that the answer is a fraction with 7r+16 on top and 4-q on the bottom. If you are writing or on the computer selecting a fraction that is stacked you don't need need the parenthesis.

4 0
1 year ago
Find the area of the circle whose equation is x2+y2=6x-8y​
Semenov [28]

Answer:

Given that the equation of a circle is :

\green{ \boxed{\boxed{\begin{array}{cc}  {x}^{2}  +  {y}^{2}  = 6x - 8y \\  =  >  {x}^{2}  +  {y}^{2}   - 6x + 8y = 0 \\  =  >  {x}^{2}  +  {y}^{2}  + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\  \\  \sf \: standard \: equation \: o f \: circle \: is :  \\   {x}^{2}  +  {x}^{2}  + 2gx + 2fy + c = 0 \\  \\  \sf \: by \: comparing \\  \\ g =  - 3 \\ f = 4 \\ c = 0 \\  \\  \sf \: radius \:  \: r =  \sqrt{ {g}^{2}  +  {f}^{2} - c }  \\  =  \sqrt{ {( - 3)}^{2} +  {4}^{2} - 0  }  \\  =  \sqrt{9 + 16}  \\   = \sqrt{25}  \\  = 5 \: unit \\  \\  \bf \: area \:  = \pi {r}^{2}  \\  = \pi \times  {5}^{2}  \\  =\pink{ 25\pi \:  { unit }^{2} }\end{array}}}}

6 0
3 years ago
Y=x^2-2x-1 and y=-3x+5 solved algebraically
eduard

Answer:

Step-by-step explanation:

y=x²-2x-1

and y=-3x+5

x²-2x-1=-3x+5

x²+x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

x=-3,2

when x=-3

y=-3×-3+5=9+5=14

when x=2

y=-3×2+5=-6+5=-1

so solutions are (-3,14) and (2,-1)

3 0
3 years ago
Find the area of the shaded polygon.
Inessa [10]

Answer:

  • 8 square units

Step-by-step explanation:

Split the polygon into 3 triangles as pictured below

<u>They have base and height:</u>

  • 4 and 3, 1 and 1, 3 and 1

<u>Find the area of 3 triangles and add up:</u>

  • A = 1/2bh
  • A = 1/2*4*3 + 1/2*1*1 + 1/2*1*3 = 6 + 1/2 + 3/2 = 8 square units

6 0
3 years ago
Read 2 more answers
The sum of 3 integers is 194. the sum of the first and second integers exceeds the third by 80. The third integer is 45 less tha
kirill115 [55]
Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45

Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239

Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102

Solving for y,
y = -2(102) + 239
y = 35

Solving for z,
z = 102 - 45
z = 57
5 0
3 years ago
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