All categories

3 years ago

Stumped someone help with geometry

Mathematics

1 answer:

Tpy6a [65]3 years ago

4 0

Notice how if you rotate and reflect the quadrilateral, you'll end up with angle F corresponding to angle S and angle C corresponding to angle T.

So A) angle F = angle S

You might be interested in

Here is a list of numbers: 47, 89, 24, 83, 59, 10, 21, 94, 17 Calculate the range.

Ivahew [28]

Answer:84

Step-by-step explanation:10 to 94 is 84

3 0

3 years ago

A system of two equations has no solution. One equation is -15x+y=18.

DerKrebs [107]

If you multiply the original equation by 3 you get -45x+3y=54, which is the exact same as A, therefore they have infinite solutions.

5 0

3 years ago

12 Using side lengths only, could the triangles be similar? 0.5 m05 1 1.5

Murljashka [212]

Answer:

$\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}$

Step-by-step explanation:

$\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/$

$\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}$

$\text{Despite this, let's check the ratios}$

$\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5$

$\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}$

8 0

3 years ago

If a=-2 and b=1, then 3a-2b=

Akimi4 [234]

If a=-2 and b=1, then
3a-2b
= 3(-2) -2(1)
= -6 -2
= -8

6 0

3 years ago

Read 2 more answers

Solve the system of equations:

Ahat [919]

Answer:

Step-by-step explanation:

z = 3

2y + z = 1

2y + 3 = 1 {substituting z =3}

2y = 1 -3

2y = -2

y = - 2/2

y = -1

2x +3y +2z = 13

2x + 3 * (-1) + 2*3 = 13 { {substituting z =3} and y = -1}

2x -3 + 6 =13

2x + 3 = 13

2x = 13 - 3

2x= 10

x = 10/2

x = 5

8 0

3 years ago