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ki77a [65]
3 years ago
7

Describe the Glide Reflection from the preimage triangle in Black to the image triangle and red​

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

We want the final coordinate of K to become (-3,1). If you reflect across the y-axis, you transform

(x,y)\mapsto(-x,y)

So, we need to move K to (3,1), and then reflect it across the y-axis. Since K starts at (-1,4), we have to move it 4 units to the right and 3 units down.

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If you rent a car for one day and drive 225 miles, the cost is $80. If you drive 350 miles in one day, the cost is $105. Let cm)
kolezko [41]

Answer:

a) (x_1 = 225, y_1 = 80) , (x_2 = 350, y_2 = 105)

And we want to find a function:

C (m) = b_1 m + b_0

We can find the slope with this formula:

b_1= \frac{105-80}{350-225}= \frac{25}{125}=0.2

And then we can use the point  (x_1 = 225, y_1 = 80) to find the intercept b_o and we got:

80 = 0.2*225 +b_0

b_0 = 80-45 = 35

So then the linear function is given by:

C(m) = 0.2 m + 35

b) For this case we have that m = 475 so we can replace into the function to find the cost like this:

C(m =475) = 0.2*475 + 35 = 130

And for the other case we have a cost of 155 and we want to find the number of miles associated so we can do this:

155 = 0.2m + 35

155-35= 120 = 0.2 m

m= \frac{120}{0.2}= 600 mi

Step-by-step explanation:

For this case we can define the following notation:

m= represent the miles travelled

C= represent the cost

Part a

For this case we have the following two points given:

(x_1 = 225, y_1 = 80) , (x_2 = 350, y_2 = 105)

And we want to find a function:

C (m) = b_1 m + b_0

We can find the slope with this formula:

b_1= \frac{105-80}{350-225}= \frac{25}{125}=0.2

And then we can use the point  (x_1 = 225, y_1 = 80) to find the intercept b_o and we got:

80 = 0.2*225 +b_0

b_0 = 80-45 = 35

So then the linear function is given by:

C(m) = 0.2 m + 35

Part b

For this case we have that m = 475 so we can replace into the function to find the cost like this:

C(m =475) = 0.2*475 + 35 = 130

And for the other case we have a cost of 155 and we want to find the number of miles associated so we can do this:

155 = 0.2m + 35

155-35= 120 = 0.2 m

m= \frac{120}{0.2}= 600 mi

6 0
3 years ago
Which mathematical statement fits the Venn diagram?
Vadim26 [7]

The answer C) One set shares some element with another.

6 0
4 years ago
Read 2 more answers
What is the answer to both of the questions
zaharov [31]
The equation is: 1/2h - 2 = 17

The total length of Josh's hike is: 38 km

1/2h - 2 = 17
1/2h = 19
h = 38
6 0
4 years ago
Read 2 more answers
If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? sin Θ = square root 2 ov
densk [106]

Answer:

\huge\boxed{\sin\theta=-\dfrac{\sqrt2}{2};\ \tan\theta=-1}

Step-by-step explanation:

We have:

\\cos\theta=\dfrac{\sqrt2}{2},\ \dfrac{3\pi}{2}

For sine use:

\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x

Substitute:

\sin^2\theta=1-\left(\dfrac{\sqrt2}{2}\right)^2\\\\\sin^2\theta=1-\dfrac{(\sqrt2)^2}{2^2}\\\\\sin^2\theta=1-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4}{4}-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4-2}{4}\\\\\sin^2\theta=\dfrac{2}{4}\to\sin\theta=\pm\sqrt{\dfrac{2}{4}}\\\\\sin\theta=\pm\dfrac{\sqrt2}{\sqrt4}\\\\\sin\theta=\pm\dfrac{\sqrt2}{2}

θ in IV quadrant, therefore sine is negative.

\sin\theta=-\dfrac{\sqrt2}{2}

For tangent use:

\tan x=\dfrac{\sin x}{\cos x}

Substitute:

\tan\theta=\dfrac{-\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}=-\dfrac{\sqrt2}{2}\cdot\dfrac{2}{\sqrt2}=-1

8 0
3 years ago
-(-(-)(-)(-10x))=-5 solve for x
Pavlova-9 [17]
The answer is c cccccc the answ er is c
5 0
3 years ago
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