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OLga [1]
4 years ago
12

The weight of an apple is 150g rounded to the nearest 5g

Mathematics
1 answer:
Gekata [30.6K]4 years ago
7 0

Answer:

The weight of an apple is 150g rounded to the nearest 5g

what is the lower bound weight of the apple

what is the upper bound of the weight of the apple

Step-by-step explanation:

The weight of an apple is 150g rounded to the nearest 5g

what is the lower bound weight of the apple

what is the upper bound of the weight of the apple

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Work out the size of angle B
eduard

Answer:

61

Step-by-step explanation:

and let c looks to be a right angle

7 0
3 years ago
Read 2 more answers
A mail order company charges 4.5% for shipping and handling. If the total order is 54.34 how much was the order total before shi
Andrews [41]

Answer:

$52

Step-by-step explanation:

Given that :

Amount charged for shipping and handling = 4.5%

Let cost of order = x

Total amount charged = 54.34

However,

total. Amount charged = (total cost + handling and shipping)

54.34 = x + 0.045x

54.34 = 1.045x

Order total before shipping = 54.34 / 1.045

Order total before shipping = 52

6 0
3 years ago
I need to know how to do Solving Systems of Equations by Elimination
vredina [299]
The point of elimination is to have one variable so example

3x + 2y = 4

7X + 3y = 5


1) Try to find a way to have one variable

7(3x + 2y = 4) ----> 21x + 14y = 28

-3(7x+ 3y = 5) -----> -21x -9y = -15


2) add

0 + 5y = 13

3) solve for the last variable

5y = 13
y = 13/5 = 2 3/5 = 2.8

4) Subsitute the variable to get the other one

3x + 2(2.8) = 4

3x + 5.6 = 4

3x = -1.6

x = 0.533333333 (continue)

The intersection would be 0.53 with a line above the 3 and 2.8. (0.5333 , 2.8)

Hope you understand!!
6 0
3 years ago
Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Select two options.
Elanso [62]

Answer:

2 and 5

Step-by-step explanation:

The slope-intercept form of a line is y=mx-b where m is slope and b is y-intercept.

The point-slope form of a line is y-y1=m(x-x1) where m is the slope and (x1,y1) is a point on the line.

The standard form a line is ax+by=c.

So anyways parallel lines have the same slope.

So if we are looking for a line parallel to 3x-4y=7 then we need to know the slope of this line so we can find the slope of our parallel line.

3x-4y=7

Goal: Put into slope-intercept form

3x-4y=7

Subtract 3x on both sides:

  -4y=-3x+7

Divide both sides by -4:

   y=\frac{-3}{-4}x+\frac{7}{-4}

Simplify:

   y=\frac{3}{4}x+\frac{-7}{4}

So the slope of this line is 3/4.  So our line that is parallel to this one will have this same slope.

So we know our line should be in the form of y=\frac{3}{4}x+b.

To find b we will use the point that is suppose to be on our new line here which is (x,y)=(-4,-2).

So plugging this in to solve for b now:

-2=\frac{3}{4}(-4)+b

-2=-3+b

3-2=b

b=1

so the equation of our line in slope-intercept form is y=\frac{3}{4}x+1

So that isn't option 1 because the slope is different.  That was the only option that was in slope-intercept form.

The standard form of a line is ax+by=c and we have 2 options that look like that.

So let's rearrange the line that we just found into that form.

y=\frac{3}{4}x+1

Clear the fractions because we only want integer coefficients by multiplying both sides by 4.

This gives us:

4y=3x+4

Subtract 3x on both sides:

-3x+4y=4

I don't see this option either.

Multiply both sides by -1:

3x-4y=-4

I do see this as a option. So far the only option that works is 2.

Let's look at point slope form now.

We had the point that our line went through was (x1,y1)=(-4,-2) and the slope,m, was 3/4 (we found this earlier).

y-y1=m(x-x1)

Plug in like so:

y-(-2)=3/4(x-(-4))

y+2=3/4 (x+4)

So option 5 looks good too.

7 0
3 years ago
Read 2 more answers
Add.<br><br> (6x3+3x2−2)+(x3−5x2−3)<br><br> Express the answer in standard form.
sergiy2304 [10]

Answer:

7x^3-2x^2-5

Step-by-step explanation:

We need to add the two terms.

(6x^3+3x^2-2)+(x^3-5x^2-3)

Solving,

Combine the like terms and adding those terms

(6x^3+3x^2-2)+(x^3-5x^2-3)\\=6x^3+3x^2-2+x^3-5x^2-3\\=6x^3+x^3+3x^2-5x^2-2-3\\=7x^3-2x^2-5

So, the answer is:

7x^3-2x^2-5

6 0
4 years ago
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