Ask question

Ask question

All categories

3 years ago

10

Write the following expression in decimal notation: 234 x 109.

1 answer:

Vikki [24]3 years ago

5 0

234x10^9
=2.34x10^11

You might be interested in

Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D

Ivahew [28]

Check the picture below.

$\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D$

$\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D$

7 0

3 years ago

Standard deviation of a normal data distribution is a _______. Group of answer choices

FrozenT [24]

Answer:

Standard deviation of a normal data distribution is a measure of data dispersion.

Step-by-step explanation:

Standard deviation is used to measure dispersion which is present around the mean data.

The value of standard deviation will never be negative.

The greater the spread, the greater the standard deviation.

Steps-

1. At first, the mean value should be discovered.

2.Then find out the square of it's distance to mean value.

3.Then total the values

4.Then divide the number of data point.

5.the square root have to be taken.

Formula-

SD= $\sqrt{\frac{(\sum{x-x)^2} }{n-1}$

Advantage-

It is used to measure dispersion when mean is used as measure of central tendency.

5 0

3 years ago

Solve on the interval [0/2pi]<br><br> 1-cos(theta) = (1/2)

Airida [17]

Answer:

Final answer is $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ .

Step-by-step explanation:

Given equation is $1-\cos\left(\theta\right)=\frac{1}{2}$

Now we need to find the solution of $1-\cos\left(\theta\right)=\frac{1}{2}$ in given interval $[0, 2\pi ]$ .

$1-\cos\left(\theta\right)=\frac{1}{2}$

$-\cos\left(\theta\right)=\frac{1}{2}-1$

$-\cos\left(\theta\right)=-\frac{1}{2}$

$\cos\left(\theta\right)=\frac{1}{2}$

which gives $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ in the given interval.

Hence final answer is $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ .

6 0

3 years ago

⚠️How do I solve this in descending order⚠️

Pani-rosa [81]

Rational. There’s nothing further that you can do with this problem

5 0

3 years ago

Need help figuring this out!

Ulleksa [173]

For this case, we have that by definition, the area of a triangle is given by:

$A = \frac {b * h} {2}$

where:

b: It's the base

h: It's the height

In this case we have:

$b = 21 \ ft\\h = 6 \ ft$

Substituting:

$A = \frac {21 * 6} {2}\\A = 63 \ ft ^ 2$

Answer:

$63 \ ft ^ 2$

6 0

3 years ago