Question

Match with the sum of the monomial and binomial. Tiles 2x2y + (x2y − 2xy2) (5xy2 − x2y) + 3x2y 4x2y + (x2y + xy2) x2y + (-2xy2 − 4x2y) Pairs 5xy2 + 2x2y -3x2y − 2xy2 3x2y − 2xy2 5x2y + xy2

Answer 1

Answer:

$1.~ 2x^2y + (x^2y - 2xy^2) = 3x^2y - 2xy^2\\2.~(5xy^2 - x^2y) + 3x^2y=5xy^2 + 2x^2y\\3.~4x^2y +(x^2y +xy^2)= 5xy^2+ 2x^2y\\3.~4x^2y + (x^2y + xy^2)=5x^2y +xy^2\\4.~x^2y + (-2xy^2 - 4x^2y)=-3x^2y - 2xy^2$

Step-by-step explanation:

We have to match the given monomials and binomials.

Monomials:

$2x^2y + (x^2y - 2xy^2)\\(5xy^2 - x^2y) + 3x^2y\\4x^2y + (x^2y + xy^2)\\x^2y + (-2xy^2 - 4x^2y)$

The given binomials are:

$5xy^2 + 2x^2y\\ -3x^2y - 2xy^2 \\3x^2y - 2xy^2\\ 5x^2y + xy^2$

Solving the monomials and matching can be done in the following manner:

$1.~ 2x^2y + (x^2y - 2xy^2)\\= 2x^2y + x^2y - 2xy^2 = 3x^2y - 2xy^2\\2.~(5xy^2 - x^2y) + 3x^2y\\=5xy^2 + 3x^2y - x^2y = 5xy^2 + 2x^2y\\3.~4x^2y + (x^2y + xy^2)\\= 4x^2y + x^2y + xy^2 = 5x^2y +xy^2\\4.~x^2y + (-2xy^2 - 4x^2y)\\= x^2y - 4x^2y-2xy^2 = -3x^2y - 2xy^2$

Answer 2

Answer:

We will simply solve them and get correct answers that will match the answers provided.

1.  $2x^{2}y+(x^{2}y-2xy^{2} )$

= $3x^{2} y-2xy^{2}$

2. $(5xy^{2}-x^{2} y)+3x^{2} y$

= $5xy^{2} +2x^{2} y$

3. $4x^{2} y+(x^{2} y+xy^{2} )$

= $5x^{2} y+xy^{2}$

4. $x^{2} y+(-2xy^{2}-4x^{2} y)$

= $-3x^{2} y-2xy^{2}$