Answer:
No
Step-by-step explanation:
If a portrait is painted in 4 hours then two portraits should be painted in 4 hours.
Answer:
the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215
Step-by-step explanation:
Let consider Q to be the opening altitude.
The mean μ = 135 m
The standard deviation = 35 m
The probability that the equipment damage will occur if the parachute opens at an altitude of less than 100 m can be computed as follows:
![P(Q](https://tex.z-dn.net/?f=P%28Q%3C100%29%20%3D%20P%28%5Cdfrac%7BX-%20135%7D%7B%5Csigma%7D%20%3C%20%5Cdfrac%7B100%20-%20135%7D%7B35%7D%7D%29)
![P(Q](https://tex.z-dn.net/?f=P%28Q%3C100%29%20%3D%20P%28z%3C%20%5Cdfrac%7B-35%7D%7B35%7D%7D%29)
![P(Q](https://tex.z-dn.net/?f=P%28Q%3C100%29%20%3D%20P%28z%3C-1%29)
![P(Q](https://tex.z-dn.net/?f=P%28Q%3C100%29%20%3D%200.1587)
If we represent R to be the number of parachutes which have equipment damage to the payload out of 5 parachutes dropped.
The probability of success = 0.1587
the number of independent parachute n = 5
the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes can be computed as:
P(R ≥ 1) = 1 - P(R < 1)
P(R ≥ 1) = 1 - P(R = 0)
The probability mass function of the binomial expression is:
P(R ≥ 1) = ![1 - (^5_0)(0.1587)^0(1-0.1587)^{5-0}](https://tex.z-dn.net/?f=1%20-%20%28%5E5_0%29%280.1587%29%5E0%281-0.1587%29%5E%7B5-0%7D)
P(R ≥ 1) =![1 - (\dfrac{5!}{(5-0)!})(0.1587)^0(1-0.1587)^{5-0}](https://tex.z-dn.net/?f=1%20-%20%28%5Cdfrac%7B5%21%7D%7B%285-0%29%21%7D%29%280.1587%29%5E0%281-0.1587%29%5E%7B5-0%7D)
P(R ≥ 1) = 1 - 0.5785
P(R ≥ 1) = 0.4215
Hence, the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes is 0.4215
This is a proportion problem. Let the monument me x feet tall.
40/x=5/6
Cross multiply:
240=5x
x=48 ft.
So the monument is 48 ft tall,
Answer:
STUV is a square
Step-by-step explanation:
segment length² = (x-x₁)² + (y-y₁)²
ST²: (-9 - 1)2 + (14 - 10)² = (-10)² + 4² = 116 (the rest follow this formula)
TU² = 116 TV² = 232 SU² = 232 SV² = 116 UV² = 116
ST = TU =SV = UV (4 sides congruent)
TV = SU (diagonal equal)
This is a square