Log 300 = a
Can be written an an exponential equation 10^a = 300
The equation which represents the given graph g(x) is 2ˣ-1.
<h3>
What is Equation?</h3>
Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.
Here, given graph passes through origin.
Put x = 0 in all the given equation and verify which equations gives result as zero.
Put x = 0 in option A
g(0) = 2⁰⁺¹ = 2 ≠ 0
in option B
g(0) = 2⁰-1 = 1 - 1 = 0
Thus, option B g(x) = 2ˣ-1 is the correct expression for the given graph.
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Answer:
Following are the response to the given points:
Step-by-step explanation:
For question 5.11:
For point a:
For all the particular circumstances, it was not an appropriate sampling strategy as each normal distribution acquired is at a minimum of 30(5) = 150 or 2.5 hours for a time. Its point is not absolutely fair if it exhibits any spike change for roughly 10 minutes.
For point b:
The problem would be that the process can transition to an in the state in less than half an hour and return to in the state. Thus, each subgroup is a biased selection of the whole element created over the last 
hours. Another sampling approach is a group.
For question 5.12:
This production method creates 500 pieces each day. A sampling section is selected every half an hour, and the average of five dimensions can be seen in a 
line graph when 5 parts were achieved.
This is not an appropriate sampling method if the assigned reason leads to a sluggish, prolonged uplift. The difficulty would be that gradual or longer upward drift in the procedure takes or less half an hour then returns to a controlled state. Suppose that a shift of both the detectable size will last hours . An alternative type of analysis should be a random sample of five consecutive pieces created every hour.
Answer:
A ≈ 78.5
Your answer was wrong because it said to round to the nearest tenth.
Step-by-step explanation:
First, to find the area of a circle, you need the radius or diameter of a circle. You can see that the radius is 5 (counting the units from E directly horizontal to the edge of the circle).
Area of a circle is:
A = πr²
A = π (5)²
Following PEMDAS (order of operations), you would do the exponent first:
A = π (25)
A ≈ 78.5
Answer: The 2nd and 3rd one are correct
Step-by-step explanation:
After reflecting it, the square itself would not change, only the position of the square. Therefore, the same line segments from the beginning which were given would be parallel.
