You must drive more than 40 miles to make option A the cheaper plan
<em><u>Solution:</u></em>
Two payment options to rent a car
Let "x" be the number of miles driven in one day
<em><u>You can pay $20 a day plus 25¢ a mile (Option A)</u></em>
25 cents is equal to 0.25 dollars
OPTION A : 20 + 0.25x
<em><u>You pay $10 a day plus 50¢ a mile (Option B)</u></em>
50 cents equal to 0.50 dollars
Option B: 10 + 0.50x
<em><u>For what amount of daily miles will option A be the cheaper plan ?</u></em>
For option A to be cheaper, Option A must be less than option B
Option A < Option B

Solve the inequality
Add -0.50x on both sides

Add - 20 on both sides,



Divide both sides by 0.25

Thus you must drive more than 40 miles to make option A the cheaper plan
Find the total number of dogs by adding each day:
Total dogs = 23
Percent of dogs: Divide the number of dogs by the total number of patients:
= 23 / 50 = 0.46 x 100 = 46%
Use the given formula to find the standard error:
Standard error = √(0.46*(1-0.46)/50) = 0.07
90%: Find Z value for 90% ( 1.645) multiply by SE:
1.645 x 0.07 = 0.115 = 0.12
Now add and subtract that value from the Percent from above:
46 + 12 = 58%
46-12 = 34%
Answer (34%, 58%)
95%: Find Z value for 95% ( 1.96) multiply by SE:
1.96 x 0.07 = 0.137 = 0.14
Now add and subtract that value from the Percent from above:
46 + 14 = 60%
46-14 = 32%
Answer (32%, 60%)
Can you tell me what do you mean exactly by menu of 8, so i can help you.
The answer is 36.
Because 20% of 36 is equal to 7.2
And 36 - 7.2 = 28.80