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Alisiya [41]
4 years ago
8

Soil pH is an important variable in the design of structures that will contact the soil. Nine test samples of soil from a potent

ial construction site gave readings of
7.3 6.5 6.4 6.1 6.0 6.5 6.2 5.8 6.7
Assuming that soil pH is normally distributed, find the 90% lower confidence bound for the true average soil pH at the site.
Mathematics
1 answer:
natta225 [31]4 years ago
8 0

Answer:

90% lower confidence bound for the true average soil pH at the site is ≈ 6.13

Step-by-step explanation:

90% Lower Confidence bound can be calculated using M-ME where

  • M is the sample mean pH (6.39)
  • ME is the margin of error from the mean

And margin of error (ME)  can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 90% confidence level (1.86)
  • s is the standard deviation of the sample PH's (0.42)
  • N is the sample size (9)

Using the numbers we get:

ME=\frac{1.86*0.42}{\sqrt{9} } ≈ 0.26

Then the 90% lower confidence bound for the true average soil pH at the site is 6.39 - 0.26 = 6.13

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Yogi is 6 years older than Michelle. The sum of their ages is 26. Write a system of linear equations to represent this informati
postnew [5]

Answer:

10 and 16, x+(x+6)=26

Step-by-step explanation:

Michelle has an age we don't know, so we put her age as x.

Yogi is 6 years older than her, so her age is x+6

Michelle=x

Yogi=x+6

we know both their ages equal 26. so we set it up as

x+(x+6)=26

combining like terms we get

2x+6=26

subtract 6 from both sides

2x=20

divide both sides by 2

x=10

now that we have the value for x, we plug it into their original ages

Michelle is 10, because her age is just x.

Yogi is 16, because her age is x+6

8 0
3 years ago
In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x
KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at  y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))  y=\frac{8}{2}=4

6 0
3 years ago
The graph below shows the height of a tunnel f(x), in feet, depending on the distance from one side of the tunnel x, in feet:
denis23 [38]
Part A) x-intercepts simply show that when the value of the function is zero. Vertex coordinates show that when the function obtains its maximum value. When x=50, function obtains its maximum value and it's 75. The function is increasing in the interval (0, 50) and decreasing in the interval (50, 100). In regard to the height and distance of the tunnel, these numbers show that decreasing and increasing intervals are symmetric. Each number from the intervals has its own pair in the corresponding interval and they are located in the same distance from the midpoint (50,75)

Part B) In order to calculate the average rate of change, we can first write the function. Using the information about the x-intercept and the vertex coordinates, we find that our function is f(x)=-0.03x^{2}+3x.
Plugging 15 and 35 in x, we can find the values of the function, i.e. 
f(15)=38.25 and f(35)=68.25.
Then, the average change is \frac{68.25-38.25}{35-15}=1.5
4 0
3 years ago
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Is this answer correct?
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Thx no that answer is not correct
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242% should be the answer
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