All categories

2 years ago

-7(x - 5) = 91 bro I need help and i must show work

Mathematics

1 answer:

fredd [130]2 years ago

5 0

Answer:

X = -8

Step-by-step explanation:

-7(x-5)=91

x-5=-13

x=-13+5

x=-8

You might be interested in

On a number line, which fraction is to the right of 3/5 ?

Snezhnost [94]

Answer:

Step-by-step explanation:

i think

4 0

3 years ago

a certain triangle has a perimeter of 3067 mi. the shortest side measures 71 mi less than the middle side and the longest side m

UkoKoshka [18]

Answer:

The measure of the shortest side is 851 miles

Step-by-step explanation:

Let

x ----> the measure of the shortest side

y ---> the measure of the middle side

z ---> the measure of the longest side

we know that

The perimeter of triangle is equal to

$P=x+y+z$

$P=3,067\ mi$

$3,067=x+y+z$ ----> equation A

the shortest side measures 71 mi less than the middle side

$x=y-71$ ----> equation B

the longest side measures 372 mi more the the middle side

$z=y+372$ ----> equation C

substitute equation B and equation C in equation A

$3,067=(y-71)+y+(y+372)$

solve for y

$3,067=3y+301\\3y=2,766\\y=922$

Find the value of x

$x=y-71\\x=922-71\\x=851$

therefore

The measure of the shortest side is 851 miles

6 0

2 years ago

The quotient of 2 and the sum of a number and 1

siniylev [52]

Answer:

2/(x + 1)

Step-by-step explanation:

4 0

2 years ago

At Sunrise Donuts you can buy 6 donuts and 2 kolaches for $8.84. One kolache and 4 donuts would cost $5.36. What is the price fo

vichka [17]

Answer:

1.34

Step-by-step explanation:

8 0

2 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

5 0

3 years ago