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2 years ago

Expand each expression In 4y5/x2

Mathematics

2 answers:

exis [7]2 years ago

4 0

Answer: Answer B

Step-by-step explanation: Let's begin

Answer: B in 4 - 2 in x + 5 in y

nordsb [41]2 years ago

3 0

Answer:

$\ln 4 -2 \ln x +5 \ln y$

Step-by-step explanation:

$\ln \dfrac{4y^5}{x^2}\\\\=\ln(4y^5) - \ln(x^2)~~~~~~~~~~~;\left[ \log_b\left( \dfrac mn \right) = \log_b m - \llog_b n \right]\\\\=\ln 4 + \ln y^5 - 2\ln x~~~~~~~~~~~~;[\log_b m^n = n \log_b m ~\text{and}~\log_b(mn) = \log_b m + \log_b n ]\\\\=\ln 4 + 5 \ln y -2 \ln x\\\\=\ln 4 -2 \ln x +5 \ln y$

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Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair

umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

Maximum value occurs at 325 at the point (0, 325)

Step-by-step explanation:

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

7 0

3 years ago

Y+23=59 solve for y i dont know if i have to add or subtract the 23 and 59

neonofarm [45]

When you move a number to the opposite side of the equation, in this occasion it will be 23- it changes to the opposite value. So us 23 is a positive value you can move it and change it to a negative. Or in other words suntract -23 from all sides of the equation, which will be equal to:
y = 59 - 23
Y = 36

7 0

4 years ago

4 to the fourth negative power multiplied by four to the fifth power

Alex Ar [27]

Simplify the following:4^5/4^4
Combine powers. 4^5/4^4 = 4^(5 - 4):4^(5 - 4)
5 - 4 = 1:Answer: 4

3 0

3 years ago

A rectangular parking area measuring 5000 ft squared is to be enclosed on three sides using chain-link fencing that costs $5.5

kaheart [24]

Answer:

Dimensions: 75.3778 ft and 66.3325 ft

Minimum price: $1658.31

Step-by-step explanation:

Let's call the length of the parking area 'x', and the width 'y'.

Then, we can write the following equations:

-> Area of the park:

x * y = 5000

-> Price of the fences:

P = 2*x*5.5 + y*5.5 + y*7

P = 11*x + 12.5*y

From the first equation, we have that y = 5000/x

Using this value in the equation for P, we have:

P = 11*x + 12.5*5000/x = 11*x + 62500/x

To find the minimum of this function, we need to take its derivative and then make it equal to zero:

dP/dx = 11 - 62500/x^2 = 0

x^2 = 65000/11

x = 250/sqrt(11) = 75.3778 ft

This is the x value that gives the minimum cost.

Now, finding y and P, we have:

x*y = 5000

y = 5000/75.3778 = 66.3325

P = 11*x + 62500/x = $1658.31

5 0

4 years ago

Which best explains why the given lines are or are not perpendicular x=-2,y=8

vesna_86 [32]

The two lines are perpendicular because both of the lines intersects

8 0

3 years ago