Answer:
-60+87d
or
87d-60
Step-by-step explanation:
-3(20+-29d)=
-60+87d
If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
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286
588
300
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The answer is -3
-12c = 43 - 7
-12c = 36
÷ -12 ÷-12
c = -3
Answer:
A) Both estimates are slightly larger, so it is reasonable.
Step-by-step explanation:
Since 1/2 = 5/10
And 1/5 = 8/40
<u>Both estimates are larger</u>