Answer: -6a-48
Step-by-step explanation:
First -6 goes into a and that turns into -6a and then -6 goes into 8 and that turns into -48 so ur answer would be: -6a-48
ur welcome
Coordinate 1 is : (0,3)
Coordinate 2 is : (-4,-2)
Coordinate 3 is : (-1,-5)
Coordinate 4 is (4,0)
Hope this helps!
The correct answer would be B! :)
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
